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- From: cary@hpcuhe.cup.hp.com (Cary Coutant)
- Newsgroups: comp.sys.hp
- Subject: Re: dump/rdump settings for dumping to an exabyte 8500 5 GB 8mm tape drive
- Message-ID: <31480309@hpcuhe.cup.hp.com>
- Date: 12 Jan 93 18:25:09 GMT
- References: <PAULLEO.93Jan11185204@comet.med.utah.edu>
- Organization: Hewlett Packard, Cupertino
- Lines: 58
-
- > Could someone tell me the settings used with dump under HPUX 8.07 for
- > writign to an exabyte 8500 5 GB 8mm tape drive?
-
- The following shows how to calculate several equivalent sets of
- dump parameters for 60m DDS tapes; you should be able to use the
- same method to figure out what to use for your tape drive.
-
- Cary Coutant
- Hewlett-Packard
- California Language Lab
-
-
- -------------------------------------------------------------------------
- Approximate capacity of 60m DDS tape = 1.3G bytes
- Approximate DDS tape density = (1.3G bytes) / (60 m) = (550K bytes/in)
-
- dump assumes an inter-record gap (IRG) of 0.3 in for density = 6250,
- 0.7 in otherwise.
-
- dump uses a default blocking factor of 10 for density < 6250,
- 32 otherwise.
- -------------------------------------------------------------------------
- density = 550000
- blocking factor = 32 (default)
- assumed IRG = 0.7 in
-
- Block length = (32K bytes/block) / (550K bytes/in) + (0.7 in) = (0.76 in)
-
- Effective tape length =
- (1.3G bytes) / (32K bytes/block) * (0.76 in/block) = (2511 ft)
- -------------------------------------------------------------------------
- density = 6250
- blocking factor = 32 (default)
- assumed IRG = 0.3 in
-
- Block length = (32K bytes/block) / (6250 bytes/in) + (0.3 in) = (5.54 in)
-
- Effective tape length =
- (1.3G bytes) / (32K bytes/block) * (5.54 in/block) = (18325 ft)
- -------------------------------------------------------------------------
- density = 1600
- blocking factor = 10 (default)
- assumed IRG = 0.7 in
-
- Block length = (10K bytes/block) / (1600 bytes/in) + (0.7 in) = (7.10 in)
-
- Effective tape length =
- (1.3G bytes) / (10K bytes/block) * (7.10 in/block) = (75113 ft)
- -------------------------------------------------------------------------
- density = 1600
- blocking factor = 32
- assumed IRG = 0.7 in
-
- Block length = (32K bytes/block) / (1600 bytes/in) + (0.7 in) = (21.18 in)
-
- Effective tape length =
- (1.3G bytes) / (32K bytes/block) * (21.18 in/block) = (70022 ft)
- -------------------------------------------------------------------------
-