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- From: mikec@hpgrla.gr.hp.com (Mike Christensen)
- Date: Thu, 24 Dec 1992 05:36:54 GMT
- Subject: Re: Re: DC Motor RFI, was Flywheel batteries as EV power source
- Message-ID: <24850026@hpgrla.gr.hp.com>
- Organization: Hewlett-Packard, Greeley, CO
- Path: sparky!uunet!cs.utexas.edu!uwm.edu!wupost!howland.reston.ans.net!usc!sdd.hp.com!hpscit.sc.hp.com!hplextra!hpfcso!hpgrla!mikec
- Newsgroups: rec.autos.tech
- References: <1992Dec22.184538.19006@progress.com>
- Lines: 29
-
- Consider the spring powered car. Let's say we take a chunk of spring steel
- and strain it to its limit (assume max stress of about 1400 N/mm^2or 200kpsi).
- How large would this cube (for simplicity sake) need to be to store 400MJ as
- the previous poster stated was required. The energy in a spring is given by
- the equation: Energy = 0.5 K x^2
- K = E A / L
-
- where E = modulus of elasticity (207,000 N/mm or 30 Mpsi)
- A = area perpendicular to the strain (L^2 for a cube)
- L = length of the spring
-
- x = L (strain)
-
- so that for a cube
- Energy = 0.5 E (strain)^2 (L)^3
-
- strain = stress/E
-
- Energy = (0.5/E)(stress)^2 (L)^3
-
- Now plug in the numbers
-
- 400,000,000,000 Nmm = (0.5/207000 N/mm^2)(1400 N/mm^2)^2 (L)^3
-
- L = 4.388 m !!!
-
- To store this kind of energy spring steel would require a cube with a
- volume of 84.5 m^3 and would weigh 676,000 kg! Not even close to something
- practical.
-