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- Newsgroups: sci.physics
- Path: sparky!uunet!cs.utexas.edu!sun-barr!ames!nsisrv!riemann.gsfc.nasa.gov!cavallo
- From: cavallo@riemann.gsfc.nasa.gov (John Cavallo)
- Subject: Re: Another antigravity device
- Message-ID: <1992Dec18.035059.20029@nsisrv.gsfc.nasa.gov>
- Sender: usenet@nsisrv.gsfc.nasa.gov (Usenet)
- Nntp-Posting-Host: riemann.gsfc.nasa.gov
- Organization: NASA Goddard Space Flight Center, Greenbelt MD
- References: <1992Dec15.013620.24161@galois.mit.edu>
- Date: Fri, 18 Dec 1992 03:50:59 GMT
- Lines: 52
-
- In article <1992Dec15.013620.24161@galois.mit.edu> jbaez@riesz.mit.edu (John C. Baez) writes:
- >Since you all liked the last one so much, here's another idea for
- >building an antigravity device. Since I am becoming associated with the
- >crackpot index, I had better firmly point out that I don't really
- >believe in antigravity devices, and I don't even spend time dreaming up
- >antigravity devices. This one is the invention of my friend Bruce K.
- >Smith, who I hasten to add doesn't really take it seriously. So
- >- see if you can spot the flaw in the idea!
- >
- >Imagine an extremely (although not infinitely) rigid crystal. It takes
- >a huge amount of energy to deform the crystal lattice ever so slightly.
- >Thus if this crystal is placed in the earth's gravitational field at sea
- >level, the curvature of space due to the gravity prevents the
- >lattice from being perfectly regular, at the cost of a large amount of
- >energy. The crystal would have much less energy if it were far away
- >from the earth where the curvature of space is less. If we make the
- >crystal rigid enough it will actually be energetically favorable for the
- >crystal to float upwards - since the decrease in its internal energy
- >will more than compensate for the increase in gravitational potential
- >energy.
- >
- >Now, I *know* that this material would have to be insanely rigid for
- >this effect to be noticeable at all -- far more rigid than any actual
- >stuff. However, we're talking questions of principle here. Is there
- >any reason *in principle* why a sufficiently rigid material wouldn't
- >levitate to get out of the earth's gravitational field - that's what I'm
- >asking.
-
- Although I don't think this is the answer you are looking for (see
- below for a guess at that), but I think there is a problem with the
- concept of increasing the stiffness of the material to increase it's
- elastic potential energy. You should note that the force (stress) on
- the material is the given at a certain point in a gravitational field.
- The elastic energy is (conceptually) stress times strain, and the
- strain is stress over stiffness, so the elastic potential energy goes
- down with stiffness. In a simpler context, a 'soft' spring supporting
- a weight will contain more energy than a stiff one (i.e. E = F^2/(2k).
- Hence you want a very pliant (is that the opposite of stiff) object.
- (Is this why my helium balloon rises and my helium cylinder doesn't? :-)
-
- I'm guessing that the general principle that you were looking for has
- something to do with the trace of stress being less than the energy
- density, but I'm not prepared to think that out right now. You should
- note that the same effect would be seen even in a Newtonian
- gravitational field, so I don't think the answer should involve special
- relativity, much less GR.
-
- --
- John M. Cavallo cavallo@okeeffe.gsfc.nasa.gov
- Scientific Visualization Studio
- Hughes STX Corporation NASA / Goddard Space Flight Center
-
-