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- Path: sparky!uunet!mcsun!sun4nl!tuegate.tue.nl!rw6.urc.tue.nl!rcbaaw
- From: rcbaaw@rw6.urc.tue.nl (Angelo Wentzler)
- Newsgroups: sci.math
- Subject: Re: Tiling problem
- Message-ID: <rcbaaw.724687510@rw6.urc.tue.nl>
- Date: 18 Dec 92 14:05:10 GMT
- References: <israel.723716857@unixg.ubc.ca> <israel.723837962@unixg.ubc.ca> <1gggutINN29q@access.usask.ca> <1gm373INNafn@access.usask.ca>
- Sender: root@tuegate.tue.nl
- Reply-To: rcbaaw@urc.tue.nl
- Lines: 63
-
- choy@skorpio.usask.ca (I am a terminator.) writes:
-
- >In article <1gggutINN29q@access.usask.ca>, choy@skorpio.usask.ca (I am a terminator.) writes:
- >|> In article <israel.723837962@unixg.ubc.ca>, israel@unixg.ubc.ca (Robert B. Israel) writes:
- >|> |> In <rcbaaw.723228012@rwb.urc.tue.nl>, rwb.urc.tue.nl (Angelo
- >|> |> Wentzler) writes:
- >|> |>
- >|> |> >Given a grid of squares, tile it with black and white tiles and make
- >|> |> >the largest possible square so that no square contained in it has four
- >|> |> >equally colored corners.
-
- >Never mind my previous post, but can such an n x n square be constructed
- >as a permutation of an n x n checkerboard?
-
- >Henry Choy
- >choy@cs.usask.ca
-
- Not all of them. There is only one 2x2 square that can be constructed from
- a 2x2 checkerboard. Manually (my search program is at home) I found some
- squares with the same property for the smaller sizes. I have also added
- some counterexamples.
-
- solution checkerboard Counterexample
-
- 10 10 11
- 01 01 01
-
- 101 101 111
- 011 010 010
- 100 101 011
-
- 1010 1010 1111
- 0110 0101 0101
- 1001 1010 0110
- 0110 0101 1100
-
-
- For such solutions the following holds:
- odd dimension: #black=#white+1
- even dimension: #black=#white
- So "balanced squares" would be a good name.
- Note that a balanced square doesn't necessarily have two white and two black
- corners.
-
- In the small example each solution is derived from the previous one, but
- I don't think that's necessary. You could make a balanced square from an
- unbalanced smaller one. Just mirror the 3x3 to get an example.
- Still, could the following be true?
-
- Any balanced NxN square must contain at least one balanced ixi subsquare for
- each 1<i<N
-
- If this were true, then the same approach for normal squares would be
- possible: just take a 2x2 balanced square (*the* 2x2 balanced square) and
- just keep expanding it to obtain one for any dimension (up to a certain
- limit...)
- Because if the above holds, those balanced ixi subsquares in particular will
- contain balanced subsquares too, etc.
-
- Could make a nice subset of the correct solutions...
-
-
- Angelo Wentzler
-