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- Newsgroups: sci.math
- Path: sparky!uunet!stanford.edu!CSD-NewsHost.Stanford.EDU!Sunburn.Stanford.EDU!pratt
- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Subject: Re: Pi in beatiful form --lost
- Message-ID: <1992Dec16.215434.25457@CSD-NewsHost.Stanford.EDU>
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- References: <BzBt9q.2HM@unccsun.uncc.edu> <1gmvieINN7al@aludra.usc.edu> <1992Dec16.144508.19371@nntpd.lkg.dec.com>
- Date: Wed, 16 Dec 1992 21:54:34 GMT
- Lines: 12
-
- In article <1992Dec16.144508.19371@nntpd.lkg.dec.com> edp@math.zk3.dec.com (Eric Postpischil) writes:
- >In article <1gmvieINN7al@aludra.usc.edu>, rmurphy@aludra.usc.edu (Bob
- >Murphy) writes:
- >
- >>(pi - 3)/4 = 1/(2*3*4) + 1/(4*5*6) + 1/(6*7*8) + ...
- >
- >The first term is 1/24, which is already greater than (pi-3)/4. Should
- >that have been an alternating series?
-
- Yep. As an alternating series the first 14 terms sum to 1/4 of 0.14151898.
- --
- Vaughan Pratt Interactive Proofs = Polynomial Space
-