home *** CD-ROM | disk | FTP | other *** search
- Xref: sparky sci.math:16980 rec.puzzles:7950
- Newsgroups: sci.math,rec.puzzles
- Path: sparky!uunet!zaphod.mps.ohio-state.edu!rpi!rogerj
- From: rogerj@aix.rpi.edu (Diversion (Jeff Rogers))
- Subject: Re: Marilyn Vos Savant's error?
- Message-ID: <0_l2xhh@rpi.edu>
- Nntp-Posting-Host: aix.rpi.edu
- References: <1992Dec15.052211.24395@CSD-NewsHost.Stanford.EDU> <1992Dec15.160000.3714@cs.cornell.edu> <BzBE0J.A6F@watdragon.uwaterloo.ca> <1992Dec15.211052.17873@cs.cornell.edu>
- Date: Tue, 15 Dec 1992 21:54:35 GMT
- Lines: 28
-
- [various other people as well as ]
- karr@cs.cornell.edu (David Karr) wrote about the subject...
-
- >How about the following rephrasing of the problem. You meet a man
- >on the street and have the following conversation:
- >"How many children have you?"
- >"Two."
- >"Is one of them a boy?"
- >"Yes."
- >What is the probability that the other child is also a boy?
-
- What I didn't see in this thread ('tho I may have missed it earlier, I just
- picked up the thread) is the simple biological argument. The probability of
- any given child being a boy[girl] is 50%. Regardless of the sexes of any
- siblings.
-
- Disregarding psychological implications:
- "I have 100 children, (at least) 99 of which are boys"
-
- The chance that the 100th child is a boy is _still_ 50%.
-
- Diversion
-
-
- --
- "I can see 'em | "Want me to create a diversion?"
- I can see 'em | Diversion
- Someone wake me when it's over" | rogerj@rpi.edu
-