home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.math
- Path: sparky!uunet!think.com!ames!news.hawaii.edu!uhunix.uhcc.Hawaii.Edu!lady
- From: lady@uhunix.uhcc.Hawaii.Edu (Lee Lady)
- Subject: Re: Function Terminology
- Message-ID: <1992Dec12.192724.21614@news.Hawaii.Edu>
- Followup-To: sci.math
- Summary: They are not the same as *morphisms*.
- Keywords: function morphism codomain
- Sender: root@news.Hawaii.Edu (News Service)
- Nntp-Posting-Host: uhunix.uhcc.hawaii.edu
- Organization: University of Hawaii (Mathematics Dept)
- References: <1gaq3tINNg9q@uwm.edu> <1992Dec11.203802.1770@CSD-NewsHost.Stanford.EDU> <Bz48w1.G5C@mentor.cc.purdue.edu>
- Date: Sat, 12 Dec 1992 19:27:24 GMT
- Lines: 43
-
- In article <Bz48w1.G5C@mentor.cc.purdue.edu> hrubin@pop.stat.purdue.edu
- (Herman Rubin) writes:
- >>In article <1gaq3tINNg9q@uwm.edu> radcliff@csd4.csd.uwm.edu
- (David G Radcliffe) writes:
- >>>Suppose I have a function f: A --> B, and C is a subset of B which
- >>>contains the image set of f. I define a function g: A --> C by
- >>>setting g(a) = f(a) for all a in A. Usually, f and g can be considered
- >>>as the same function, but sometimes the distinction is important.
- >> ...
- >The function is exactly the same. A function, in whatever foundational
- >system is used, is something which takes arguments in a domain and
- >operates on them. The image set depends only on f and A. Which
- >superset of the range is used does not affect the function.
-
- Technically your answer is correct but the issue is real and I wish there
- were a good answer for it, not only as regards notation but as regards
- terminology. In teaching courses such as abstract algebra I usually call
- g above the "restriction" of f, with an audible emphasis to indicate
- quotation marks around the word restriction or a verbal footnote to
- indicate that I am using it in a non-standard sense.
-
- The point is that although most terminlogy would call f and g the
- same *function*, from a categorical point of view they are not the same
- *morphism*. Given h:B --> D, I can form the composition hf but I
- cannot form the composition hg because morphisms can only be composed
- when the "codomain" of the one agrees with the domain of the other.
-
- This is not mere nitpicking, since if F is a functor then F(g) may be
- very different from F(f). One may be a monomorphism (one-to-one), for
- instance, and the other not. In a course in algebra (or algebraic
- topology) it is very important that students understand the importance of
- this apparently trivial distinction.
-
- I think that your comment, Herman, reinforces the point I made earlier in
- another thread that many mathematicians in fields such as analysis find
- category theory totally irrelevant to what they do and never think in
- categorical terms.
-
- --
- It is a poor sort of skepticism which merely delights in challenging
- those claims which conflict with one's own belief system.
- --Bogus quote
- lady@uhunix.uhcc.hawaii.edu lady@uhunix.bitnet
-