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- Path: sparky!uunet!stan!not-for-mail
- From: tls@solbourne.com (Tom Schreur)
- Newsgroups: rec.photo
- Subject: exposure compensation with extention, how?
- Date: 18 Nov 1992 17:20:12 -0700
- Organization: Solbourne Computer, Inc., Longmont, CO USA
- Lines: 31
- Message-ID: <1eemjsINNb8@koh_samui.solbourne.com>
- NNTP-Posting-Host: koh_samui.solbourne.com
-
-
- OK netters, I need some help.
-
- I want to do some macro work with the 4x5. I'm trying to understand how
- to compensate for extention when figuring out exposure.
-
-
- Lets say I'm using a 135mm f5.6 lense with the aperature at f8 and procced from there.
-
- my thought processes was to:
- 1.) figure diameter of a given aperature ( diameter of aperature = focal length/fstop ).
- 135/8 = 16.875mm for my stated lense.
-
- 2.) figure extention past the 135mm of the lense ( lets say 100mm ). Add this to the
- focal length of the lense ( 135mm + 100mm = 235mm ).
-
- 3.) divide the result of step 2 by the result of step 1 to get my effective aperature.
- 235mm/16.875mm = 13.9
-
- This would then be the f-stop I would use in flash calculations.
-
- Right? Wrong?
-
- Any input would be welcomed.
-
- thank,
-
- tls
-
- tls@solbourne.com
-
-