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- Newsgroups: rec.motorcycles
- Path: sparky!uunet!tcsi.com!sparcplug!markk
- From: markk@tcs.com (Mark Kromer)
- Subject: Re: Slip-sliding away (was Re: What would you ride...)
- In-Reply-To: ranck@joesbar.cc.vt.edu (Wm. L. Ranck)
- Message-ID: <1992Nov20.213730.28942@tcsi.com>
- Originator: markk@sparcplug
- Sender: markk@tcs.com
- Reply-To: markk@tcs.com (Mark Kromer)
- Organization: Teknekron Communications Inc.
- References: <1992Nov18.194212.6271@colorado.edu> <9817@vtserf.cc.vt.edu>
- Date: Fri, 20 Nov 1992 21:37:30 GMT
- Lines: 28
-
-
- In article <9817@vtserf.cc.vt.edu>, ranck@joesbar (Wm. L. Ranck) writes:
- >Alex Matthews (alex@lyra.colorado.edu) wrote:
- >: Future contributors to this thread should first complete the following
- >: brain-teaser:
- >:
- >: "You are riding your bike in a straight line. Is your front wheel rotating
- >: about its hub, or about its contact point with the road, or both, or
- >: neither?"
- >
- >The wheel is definitely rotating about its hub. It is not rotating about its
- >contact patch. Envision the wheel spinning at the same time it is travelling
- >forward one inch off the road. OK, now that you have this mini-wheelie
- >pictured let's assume that the tire touches down and contiues spinning at the
- >same speed and so does forward travel. It should be obvious that there is
- >not rotation around the contact patch. This is valid for straight line only.
-
- If you are talking about pure rotation (rotation without translation)
- relative to the ground, then you want to find the point on the tire
- that has 0 velocity relative to the ground. That point is at the
- contact patch. Like the contact patch, it's location on the ground
- and tire changes constantly so we have to use terms like instantaneous
- center of rotation.
-
- --
- )V(ark)< markk@tcs.com DoD #400
- 1988 FZR400 1985 ZX900 Ninja 1977 RD400D
- "I'm just makin' this up as I go along."
-