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- From: snyder@henry.ece.cmu.edu (John Snyder)
- Newsgroups: sci.physics
- Subject: Re: ... an infinite mesh of 1ohm resistors ...
- Message-ID: <1992Jul28.093201.10671@fs7.ece.cmu.edu>
- Date: 28 Jul 92 09:32:01 GMT
- Article-I.D.: fs7.1992Jul28.093201.10671
- References: <1992Jul25.210947.12316@cs.yale.edu> <1992Jul27.210947.5820@fs7.ece.cmu.edu> <1992Jul28.000844.27051@mixcom.com>
- Sender: news@fs7.ece.cmu.edu (USENET News System)
- Organization: Physics Department, Carnegie Mellon University
- Lines: 71
-
- In article <1992Jul28.000844.27051@mixcom.com> ttyytt@mixcom.com (Adam Costello) writes:
- >In article <1992Jul27.210947.5820@fs7.ece.cmu.edu> snyder@henry.ece.cmu.edu (John Snyder) writes:
- >>
- >>I believe that you are missing the point of the previous post here.
- >
- >But I think you are missing the point of the second post. The "solution"
- >involved imagining that you could inject an amp of current into a network
- >of resistors. No capacitors! Where is the charge supposed to go?
- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
-
- Hunh? What do capacitors have to do with it?
- Surely, you can pass 1 amp through a network of resistors with
- no capacitors present. We solved *MANY* such problems in Electrical
- Engineering 101 (groan! (:^)). The current goes in at terminal A, and
- out at terminal B. I cannot seem to locate the original problem, but my
- recollection is that there were 2 terminals involved.
-
- >Regardless of whether this can be done in the laboratory, there's still
- >the question of whether it can be done in the mind. Certainly, if the
- >network were finite, it would make no sense. Does the infinitude of the
- >network allow a source with no sink? We can argue that it does this way:
- >
- >Consider this sequence of networks:
- >
- >+-----+-----+ +-----+-----+-----+-----+
- >| | | | | | | |
- >| / | | / / / |
- >| \ | | \ \ \ |
- >| / | | / / / |
- >| |A | | | | | |
- >+-/\/-+-/\/-+ +-/\/-+-/\/-+-/\/-+-/\/-+
- >| | | | | | | |
- >| / | | / / / |
- >| \ | | \ \ \ |
- >| / | | / / / |
- >| | |B | | |A | |
- >+-----+-----+ +-/\/-+-/\/-+-/\/-+-/\/-+ And so on...
- > | | | | |
- > | / / / |
- > | \ \ \ |
- > | / / / |
- > | | | | |
- > +-/\/-+-/\/-+-/\/-+-/\/-+
- > | | | | |
- > | / / / |
- > | \ \ \ |
- > | / / / |
- > | | | | |B
- > +-----+-----+-----+-----+
- >
- >In each network, connect a 1 amp current source from B to A. In the
- >limit, we have the infinite network with a source and no sink. I'm
- >still not convinced, because I'm not sure "limit" makes sense here.
- >Any comments?
- >
- >AMC
-
-
- Just because the network is infinite does *NOT* mean that the resistance
- is infinite. Consider the following simple example: A parallel circuit,
- one leg has 1 ohm resistance, the other has near-infinite (or infinite)
- resistance. What is the equivalent resistance? (surely not infinite)
- Can you pass current through it? (of course). Now consider that near-
- infinite resistor to be a huge network of resistors. The solution is still
- the same. How much current flows thru that huge network leg? (Almost none)
- I believe that the original post had 2 terminals. One does not
- talk about the resistance at a point, only the equivalent resistance between
- 2 terminals.
-
- John
- snyder@henry.ece.cmu.edu
-