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- Newsgroups: sci.math
- Path: sparky!uunet!cs.utexas.edu!tamsun.tamu.edu!cmenzel
- From: cmenzel@tamsun.tamu.edu (Christopher P Menzel )
- Subject: Re: Stupid question about FLT
- Message-ID: <1992Jul24.174752.25049@tamsun.tamu.edu>
- Organization: Texas A&M University, College Station
- References: <BrJtH1.24x@cs.psu.edu> <1992Jul19.195047.28807@galois.mit.edu> <1992Jul19.231456.21018@mailer.cc.fsu.edu>
- Date: Fri, 24 Jul 1992 17:47:52 GMT
- Lines: 26
-
- In article <1992Jul19.231456.21018@mailer.cc.fsu.edu> rose@fsu1.cc.fsu.edu writes:
- >I suggest that if FLT is undecidable in one model of the integers, it is
- >undecidable is ALL models. It is no paradox that if it is undecidable, then
- >it is true. This is because undecidable simply means unable to prove true or
- >false. If we cannot (in principle) prove FLT false, this means that it IS
- >NOT FALSE.
-
- You seem to be saying that inability to prove the negation of a
- sentence implies that the sentence isn't false. But, for example, we
- cannot prove (in PA) the negation of the G\"{o}del sentence for PA,
- but (reasoning in the usual way in our metatheory) it is false (in the
- natural numbers) all the same.
-
-
- >Whereas, it might be possible that no method exist to prove FLT
- >is true. Since we say that FLT is true if it is not false, we say that if
- >FLT is undecidable, then it is true.
-
- Correct me if I'm wrong, but I *think* the reason that the
- undecidability of FLT implies its truth is simply that any
- counterexample to FLT (i.e., a formula of the form a^n + b^n = c^n)
- would be provable in PA. Hence, FLT can't be both undecidable and
- false.
-
- Chris Menzel
-
-