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ARCHPIPE.TXT
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1985-09-09
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ARCHPIPE.TXT
ARCH PIPE PROGRAM
ARCHPIPE DOCUMENTATION: Archpipe culvert, metal or concrete - program
written in house with some reference to "Hydraulic Analysis of Pipe Arch
Programs" (BPR Program HY-2) dtd. May, 1969.
1. DO YOU WANT PRINTOUT ON (SCREEN=0 PRINTER=1 BOTH=2)
With the SCREEN option, everything will be displayed on the screen
therefore no hard copy will be obtained.
With the PRINTER option, there would be no display of the output on
the screen, therefore reference must be made to the printout in
order to run the Water Surface Profile and the Headwater
computations.
With the BOTH option, output will be displayed on the screen so
Water Surface Profile and the Headwater computation could be
performed without any reference to the printout.
2. Enter TYPE? METAL=0, CONCRETE=1
3. ENTER DISCHARGE? (in cfs)
4. ENTER SLOPE? (in ft./ft.)
5. ENTER DEPTH OF MATERIAL? (in ft.)
Type a value for the depth of material if invert of pipe is buried
below the flowline.
Type 0 if not buried.
6. ENTER MANNING'S N OR 0?
If 0 is entered then program will calculate "N" based on equation
from FHWA publication (only for metal pipes).
P.C.'s OUTPUT: (EXAMPLE)
*****************CONCRETE AND METAL PIPE ARCH PROGRAM*******************
DISCHARGE=500.00 cfs SLOPE=0.00500
MANNING'S 'N' = 0.012 DEPTH OF MATERIAL = 0
7. IS DATA CORRECT? YES=0 NO=1
If NO, type 1 - will repeat all previous questions.
8. ENTER RISE IN INCHES EX.=77.3?
For this example - use 72 inches
P.C.'s OUTPUT
---- CONCRETE ARCH ----
SPAN = 115.6 INCHES OR 9.63 FEET
RISE = 72.0 INCHES OR 6.00 FEET
C.R. = 18.0 INCHES OR 1.50 FEET
0.925 * RISE = 5.55 FT.
TOTAL AREA = 45.30 SQ. FT. TOTAL PERIMETER = 25.20 FT.
CRITICAL DEPTH = 4.68 FT. VELOCITY = 12.75 FT./SEC.
WETTED PER. = 17.82 FT. WATER WIDTH = 6.70 FT.
MANNING'S "N" = 0.012
NORMAL DEPTH = 4.01 FT. VELOCITY = 14.58 FT./SEC.
WETTED PER. = 16.01 FT. WATER WIDTH = 7.90 FT.
MANNING'S "N" = 0.012
9. NEED WATER WATER SURFACE PROFILE? YES = 0 NO = 1?
If yes, type 0 for partially full flow condition. This is
necessary for calculating the headwater.
If yes:
a. ENTER INITIAL DEPTH OVER FLOWLINE?
Means starting depth over flowline. Over flowline
specified because pipe invert can be buried and
therefore, the starting depth required is from the top
of the material. If not buried then the starting depth
is from the invert of the pipe. Please refer to
sub-critical and super-critical flow profiles to determine
initial depth.
b. ENTER FINAL DEPTH OVER FLOWLINE?
Please refer to sub-critical and super-critical
flow profiles.
c. ENTER INCREMENT?
Means depth increment to be used to go from the
initial depth to the final depth. The smaller the
depth increment, the more accurate the water surface
profile. It is recommended that a 0.10 ft. increment
be the smallest increment used unless in a very
critical area.
d. IS DATA CORRECT? YES = 0 NO = 1?
Gives opportunity to change wrong input or to change
the initial or final depth.
P.C.'s OUTPUT:
INITIAL DEPTH = 5.5 FINAL DEPTH = 4.68 INCREMENT = .1
10. IS DATA CORRECT? YES = 0 NO = 1? 0
DEPTH-FT VELOCITY DELTA X SUM OF X'S -FT HYD WET WAT "N"
(CONTROL IS: NEG=DOWNSTREAM; POS=UPSTREAM) RAD PER SURF
5.50 11.41 2.116 20.72 4.32 .012
5.40 11.52 27.26- 27.26- 2.139 20.29 4.71 .012
5.30 11.66 24.54- 51.80- 2.158 19.88 5.06 .012
5.20 11.80 21.86- 73.66- 2.172 19.51 5.38 .012
5.10 11.95 19.09- 92.75- 2.184 19.15 5.67 .012
5.00 12.12 16.10- 108.85- 2.192 18.81 5.94 .012
4.90 12.30 12.74- 121.58 2.198 18.49 6.20 .012
4.80 12.50 8.80- 130.38- 2.201 18.18 6.44 .012
4.70 12.71 4.00- 134.39- 2.201 17.88 6.66 .012
NEW?: SIZE=1 HYDRAULICS=2 PROFILE=3 HEAD WATER =4
MATERIAL (METAL OR CONCRETE)=5 DONE=6
After this message is printed out then:
the P.C. is waiting for a number from 1 thru 6. If #1 is typed
then the P.C. will ask for new rise. If #2 is typed then P.C. will ask
for a new discharge, slope, manning's "n" and depth of material. If #3 If #3 is
is typed then P.C will ask for new initial depth, final depth and
increment to run a new Water Surface Profile. If #4 is typed then P.C.
will ask appropriate questions necessary to calculate headwater.
If #5 is typed the program will ask for a new material, concrete or
metal. If #6 is typed the program execution will STOP.
FOR NO. 4 (HEADWATER), summary of hydraulics and size is printed.
P.C.'s OUTPUT
################ CONCRETE AND METAL PIPE-ARCH PROGRAM #################
DISCHARGE= 500.00 CFS SLOPE = 0.00500
MANNING'S 'N' = 0.012 DEPTH OF MATERIAL = 0
---- CONCRETE ARCH ----
SPAN = 115.6 INCHES OR 9.63 FEET
C.R. = 18.0 INCHES OR 1.50 FEET
TOTAL AREA = 45.30 SQ. FT. TOTAL PERIMETER = 25.20 FT.
CRITICAL DEPTH = 4.68 FT. VELOCITY = 12.75 FT./SEC.
NORMAL DEPTH = 4.01 FT. VELOCITY = 14.58 FT./SEC.
>>>>>>>>>>>>>>>>>>>>>>>> HEAD WATER CALCULATIONS <<<<<<<<<<<<<<<<<<<<<<
12. FULL FLOW CONDITION YES = 1 NO = 0
This is the first question leading into the headwater calcula-
tions.
If yes (type 1), means the pipe is flowing full.
If no (type 0), means the pipe is flowing partially full and
Water Surface Profile should have been run before proceeding
into headwater computations.
If no (type 0), then P.C. will ask for:
a. FLOW DEPTH AT THE INLET?
Knowing the culvert length, (130 ft.) refer to Water Surface
Profile printout and find the flow depth at the inlet to be 4.8 ft.
b. INLET VELOCITY?
From the Water Surface Profile find the inlet velocity for the
above flow depth to be 12.50 fps.
c. INLET LOSS COEFFICIENT (Ke)?
Use 0.50 for apron (or headwall), 0.70 for mitered 0.90 for
projecting.
d. ENTER APPROACH VELOCITY? (in ft./sec.)
For the majority of times, zero should be entered. In
locations such as a county ditch with no overbank flow where
the opening of the culvert and the approach channel below the
design stage is approximately the same, then an average velocity
of approach is entered. A velocity head of approach (V^2/2g) is
subtracted from the total head.
P.C.'s OUTPUT
>>>>>>>>>>>>>>>>>>>>>>>> HEAD WATER CALCULATIONS <<<<<<<<<<<<<<<<<<<<<<
///// OUTLET CONTROL /////
FULL FLOW CONDITION 1=YES 0=NO? 0
FLOW DEPTH AT INLET? 4.8
FLOW DEPTH AT INLET = 4.80 FEET
INLET VELOCITY? 12.5
INLET VELOCITY = 12.50 FT/SEC
INLET LOSS COEFFICIENT (KE)= 0.5000
ENTER APPROACH VELOCITY? 0
APPROACH VELOCITY 0.00 FT/SEC
IS DATA CORRECT 0=YES 1=NO? 0
OUTLET CONTROL HW FOR PARTIAL FLOW = 8.44 FEET
//////// INLET CONTROL ////////
Note: The calculated headwater for outlet control of 8.44 ft. is based
on the inlet flowline.
INLET TYPE 1=PROJECTING, 2=MITERED, 3=APPRON (OR HEADWATER)
Enter the number (3 in this example).
P.C.'s OUTPUT
INLET TYPE
MITERED
INLET CONTROL HW = 8.41 FEET
The inlet control headwater of 8.41 feet is compared to the outlet
control headwater of 8.44 feet and the largest one is chosen i.e.
the 8.44 feet as the final headwater.
g. NEW? SIZE=1 OPTION=2 HYDRAULICS=3 PROFILE=4 HEADWATER=5
This is a printed message.
This is a looping statement to give opportunity for new input
values in the specific area stated.
IF YES: (To the previous question of "FULL FLOW CONDITION?")
a. ENTER LENGTH OF CULVERT? (in ft.)
b. INLET LOSS COEFFICIENT (Ke)?
USE 0.50 FOR APRON (OR HEADWALL), 0.70 FOR MITERED, 0.90 FOR
PROJECTING
c. ENTER APPROACH VELOCITY? (in ft./sec.)
For the majority of times, zero should be entered. In
locations such as a county ditch with no overbank flow where
the opening of the culvert and the approach channel below the
design stage is approximately the same, then an average velocity
of approach is entered. A velocity head of approach (V^2/2g) is
subtracted from the total head.
d. ENTER LARGER VALUE (Dc+D)/2
Enter (Dc+D)/2 whichever is larger.
To this value, the total head is added.
P.C.'s OUTPUT
///// OUTLET CONTROL /////
LENGTH OF CULVERT = 130 FEET
INLET LOSS COEFFICIENT (Ke) = 0.5000
APPROACH VELOCITY = 0.00 FT/SEC
FULL FLOW VELOCITY = 11.04 FEET/SEC
(Dc+D)/2 = 5.34 FEET
INPUT VALUE (Dc+D)/2 OR TW = 6.50 FEET
OUTLET CONTROL HW FOR FULL FLOW 9.17 FEET
///// INLET CONTROL /////
The calculated headwater for outlet control of 9.17 feet is
based on the inlet flowline.
e. INLET TYPE? 1=PROJECTING, 2=MITERED, 3=APRON (OR HEADWALL)
The program is looking for a number from 1 to 3 as before.
P.C.'s OUTPUT
Same output as before (for the same "INLET TYPE' number 1).
In the example, the headwater is 8.41 ft.
The inlet control headwater value of 8.41 ft. is compared with
the outlet control headwater value of 9.17 and the largest is
chosen, i.e. 9.17 ft.
f. NEW? SIZE=1 OPTION=2 HYDRAULICS=3 PROFILE=4 HEADWATER=5
DONE=6
NOTE: For metal arch option, a similiar procedure as for concrete arch
should be followed.