ARCHPIPE.TXT ARCH PIPE PROGRAM ARCHPIPE DOCUMENTATION: Archpipe culvert, metal or concrete - program written in house with some reference to "Hydraulic Analysis of Pipe Arch Programs" (BPR Program HY-2) dtd. May, 1969. 1. DO YOU WANT PRINTOUT ON (SCREEN=0 PRINTER=1 BOTH=2) With the SCREEN option, everything will be displayed on the screen therefore no hard copy will be obtained. With the PRINTER option, there would be no display of the output on the screen, therefore reference must be made to the printout in order to run the Water Surface Profile and the Headwater computations. With the BOTH option, output will be displayed on the screen so Water Surface Profile and the Headwater computation could be performed without any reference to the printout. 2. Enter TYPE? METAL=0, CONCRETE=1 3. ENTER DISCHARGE? (in cfs) 4. ENTER SLOPE? (in ft./ft.) 5. ENTER DEPTH OF MATERIAL? (in ft.) Type a value for the depth of material if invert of pipe is buried below the flowline. Type 0 if not buried. 6. ENTER MANNING'S N OR 0? If 0 is entered then program will calculate "N" based on equation from FHWA publication (only for metal pipes). P.C.'s OUTPUT: (EXAMPLE) *****************CONCRETE AND METAL PIPE ARCH PROGRAM******************* DISCHARGE=500.00 cfs SLOPE=0.00500 MANNING'S 'N' = 0.012 DEPTH OF MATERIAL = 0 7. IS DATA CORRECT? YES=0 NO=1 If NO, type 1 - will repeat all previous questions. 8. ENTER RISE IN INCHES EX.=77.3? For this example - use 72 inches P.C.'s OUTPUT ---- CONCRETE ARCH ---- SPAN = 115.6 INCHES OR 9.63 FEET RISE = 72.0 INCHES OR 6.00 FEET C.R. = 18.0 INCHES OR 1.50 FEET 0.925 * RISE = 5.55 FT. TOTAL AREA = 45.30 SQ. FT. TOTAL PERIMETER = 25.20 FT. CRITICAL DEPTH = 4.68 FT. VELOCITY = 12.75 FT./SEC. WETTED PER. = 17.82 FT. WATER WIDTH = 6.70 FT. MANNING'S "N" = 0.012 NORMAL DEPTH = 4.01 FT. VELOCITY = 14.58 FT./SEC. WETTED PER. = 16.01 FT. WATER WIDTH = 7.90 FT. MANNING'S "N" = 0.012 9. NEED WATER WATER SURFACE PROFILE? YES = 0 NO = 1? If yes, type 0 for partially full flow condition. This is necessary for calculating the headwater. If yes: a. ENTER INITIAL DEPTH OVER FLOWLINE? Means starting depth over flowline. Over flowline specified because pipe invert can be buried and therefore, the starting depth required is from the top of the material. If not buried then the starting depth is from the invert of the pipe. Please refer to sub-critical and super-critical flow profiles to determine initial depth. b. ENTER FINAL DEPTH OVER FLOWLINE? Please refer to sub-critical and super-critical flow profiles. c. ENTER INCREMENT? Means depth increment to be used to go from the initial depth to the final depth. The smaller the depth increment, the more accurate the water surface profile. It is recommended that a 0.10 ft. increment be the smallest increment used unless in a very critical area. d. IS DATA CORRECT? YES = 0 NO = 1? Gives opportunity to change wrong input or to change the initial or final depth. P.C.'s OUTPUT: INITIAL DEPTH = 5.5 FINAL DEPTH = 4.68 INCREMENT = .1 10. IS DATA CORRECT? YES = 0 NO = 1? 0 DEPTH-FT VELOCITY DELTA X SUM OF X'S -FT HYD WET WAT "N" (CONTROL IS: NEG=DOWNSTREAM; POS=UPSTREAM) RAD PER SURF 5.50 11.41 2.116 20.72 4.32 .012 5.40 11.52 27.26- 27.26- 2.139 20.29 4.71 .012 5.30 11.66 24.54- 51.80- 2.158 19.88 5.06 .012 5.20 11.80 21.86- 73.66- 2.172 19.51 5.38 .012 5.10 11.95 19.09- 92.75- 2.184 19.15 5.67 .012 5.00 12.12 16.10- 108.85- 2.192 18.81 5.94 .012 4.90 12.30 12.74- 121.58 2.198 18.49 6.20 .012 4.80 12.50 8.80- 130.38- 2.201 18.18 6.44 .012 4.70 12.71 4.00- 134.39- 2.201 17.88 6.66 .012 NEW?: SIZE=1 HYDRAULICS=2 PROFILE=3 HEAD WATER =4 MATERIAL (METAL OR CONCRETE)=5 DONE=6 After this message is printed out then: the P.C. is waiting for a number from 1 thru 6. If #1 is typed then the P.C. will ask for new rise. If #2 is typed then P.C. will ask for a new discharge, slope, manning's "n" and depth of material. If #3 If #3 is is typed then P.C will ask for new initial depth, final depth and increment to run a new Water Surface Profile. If #4 is typed then P.C. will ask appropriate questions necessary to calculate headwater. If #5 is typed the program will ask for a new material, concrete or metal. If #6 is typed the program execution will STOP. FOR NO. 4 (HEADWATER), summary of hydraulics and size is printed. P.C.'s OUTPUT ################ CONCRETE AND METAL PIPE-ARCH PROGRAM ################# DISCHARGE= 500.00 CFS SLOPE = 0.00500 MANNING'S 'N' = 0.012 DEPTH OF MATERIAL = 0 ---- CONCRETE ARCH ---- SPAN = 115.6 INCHES OR 9.63 FEET C.R. = 18.0 INCHES OR 1.50 FEET TOTAL AREA = 45.30 SQ. FT. TOTAL PERIMETER = 25.20 FT. CRITICAL DEPTH = 4.68 FT. VELOCITY = 12.75 FT./SEC. NORMAL DEPTH = 4.01 FT. VELOCITY = 14.58 FT./SEC. >>>>>>>>>>>>>>>>>>>>>>>> HEAD WATER CALCULATIONS <<<<<<<<<<<<<<<<<<<<<< 12. FULL FLOW CONDITION YES = 1 NO = 0 This is the first question leading into the headwater calcula- tions. If yes (type 1), means the pipe is flowing full. If no (type 0), means the pipe is flowing partially full and Water Surface Profile should have been run before proceeding into headwater computations. If no (type 0), then P.C. will ask for: a. FLOW DEPTH AT THE INLET? Knowing the culvert length, (130 ft.) refer to Water Surface Profile printout and find the flow depth at the inlet to be 4.8 ft. b. INLET VELOCITY? From the Water Surface Profile find the inlet velocity for the above flow depth to be 12.50 fps. c. INLET LOSS COEFFICIENT (Ke)? Use 0.50 for apron (or headwall), 0.70 for mitered 0.90 for projecting. d. ENTER APPROACH VELOCITY? (in ft./sec.) For the majority of times, zero should be entered. In locations such as a county ditch with no overbank flow where the opening of the culvert and the approach channel below the design stage is approximately the same, then an average velocity of approach is entered. A velocity head of approach (V^2/2g) is subtracted from the total head. P.C.'s OUTPUT >>>>>>>>>>>>>>>>>>>>>>>> HEAD WATER CALCULATIONS <<<<<<<<<<<<<<<<<<<<<< ///// OUTLET CONTROL ///// FULL FLOW CONDITION 1=YES 0=NO? 0 FLOW DEPTH AT INLET? 4.8 FLOW DEPTH AT INLET = 4.80 FEET INLET VELOCITY? 12.5 INLET VELOCITY = 12.50 FT/SEC INLET LOSS COEFFICIENT (KE)= 0.5000 ENTER APPROACH VELOCITY? 0 APPROACH VELOCITY 0.00 FT/SEC IS DATA CORRECT 0=YES 1=NO? 0 OUTLET CONTROL HW FOR PARTIAL FLOW = 8.44 FEET //////// INLET CONTROL //////// Note: The calculated headwater for outlet control of 8.44 ft. is based on the inlet flowline. INLET TYPE 1=PROJECTING, 2=MITERED, 3=APPRON (OR HEADWATER) Enter the number (3 in this example). P.C.'s OUTPUT INLET TYPE MITERED INLET CONTROL HW = 8.41 FEET The inlet control headwater of 8.41 feet is compared to the outlet control headwater of 8.44 feet and the largest one is chosen i.e. the 8.44 feet as the final headwater. g. NEW? SIZE=1 OPTION=2 HYDRAULICS=3 PROFILE=4 HEADWATER=5 This is a printed message. This is a looping statement to give opportunity for new input values in the specific area stated. IF YES: (To the previous question of "FULL FLOW CONDITION?") a. ENTER LENGTH OF CULVERT? (in ft.) b. INLET LOSS COEFFICIENT (Ke)? USE 0.50 FOR APRON (OR HEADWALL), 0.70 FOR MITERED, 0.90 FOR PROJECTING c. ENTER APPROACH VELOCITY? (in ft./sec.) For the majority of times, zero should be entered. In locations such as a county ditch with no overbank flow where the opening of the culvert and the approach channel below the design stage is approximately the same, then an average velocity of approach is entered. A velocity head of approach (V^2/2g) is subtracted from the total head. d. ENTER LARGER VALUE (Dc+D)/2 Enter (Dc+D)/2 whichever is larger. To this value, the total head is added. P.C.'s OUTPUT ///// OUTLET CONTROL ///// LENGTH OF CULVERT = 130 FEET INLET LOSS COEFFICIENT (Ke) = 0.5000 APPROACH VELOCITY = 0.00 FT/SEC FULL FLOW VELOCITY = 11.04 FEET/SEC (Dc+D)/2 = 5.34 FEET INPUT VALUE (Dc+D)/2 OR TW = 6.50 FEET OUTLET CONTROL HW FOR FULL FLOW 9.17 FEET ///// INLET CONTROL ///// The calculated headwater for outlet control of 9.17 feet is based on the inlet flowline. e. INLET TYPE? 1=PROJECTING, 2=MITERED, 3=APRON (OR HEADWALL) The program is looking for a number from 1 to 3 as before. P.C.'s OUTPUT Same output as before (for the same "INLET TYPE' number 1). In the example, the headwater is 8.41 ft. The inlet control headwater value of 8.41 ft. is compared with the outlet control headwater value of 9.17 and the largest is chosen, i.e. 9.17 ft. f. NEW? SIZE=1 OPTION=2 HYDRAULICS=3 PROFILE=4 HEADWATER=5 DONE=6 NOTE: For metal arch option, a similiar procedure as for concrete arch should be followed.