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UNIX
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1992-12-07
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UNIX & XENIX & Terminals & Others
The defaults for the modem are &C0 &D0, autoanswer OFF. For
most PC applications you set &C1 &D2. Unix and Xenix do not seem
to be standardized. Try combinations; (AT&F sets defaults)
AT&F
AT&F&C1
AT&F&D2
AT&F&C1&D2
(some rare cases may want &D3 - see manual)
If the device cannot issue the init string to the modem each
time, finish the line with &W and it will be saved to NV ram so
the modem will power-up with that configuration.
AT&F&C1&W (example)
To set autoanswer to ON the command is S0=1
ATS0=1
Commands may be combined on one line, AT&F at the start, &W
at the end. The modem will also 'wake up' at the same speed,
parity, bits, and stop bit that you were using at that time the
AT.....&W command was issued. So always use the fastest (up to
19,200) that the modem and port support when you do the AT...&W.
On some devices the &Sx and &Rx may need to be changed from
default (see manual).
Another default is E1 (command echo). Many systems prefer
not to get command echos, so E0 should be included in the
string.
Systems which do not want reponses to commands or CONNECT
responses, include Q1 in the string (default is Q0 to echo
responses). Q2 will let the CONNECT reponses through, but inhibit
command responses.
In most cases the BPS should be 19,200 and CTS/RTS hardware
flow control.
In working with one SCO Unix user these strings worked.
ANSWER modem: AT&F&C1E0Q1S0=1 (&W)
calling modem:AT&FQ1S0=0 (&W)
One Min-computer user reports this works:
ANSWER modem: AT&FE0&R1S0=1 (&W)
calling modem:AT&F&C1&R1 (&W)
The &W also saves the 'current' speed, parity, bits and stop
bit, so the modem will wake-up with those defaults.
The default for Zoom 'V' series modems is to use speed-
buffering. This means you set your port at 19,200 when you set
the modem, and when you use the modem. The modem takes care of
modem-modem speed.
Don Hinds - Zoom Tech
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