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MAKECRC.C
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C/C++ Source or Header
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1991-10-03
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2KB
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61 lines
/* Not copyrighted 1990 Mark Adler */
#include <stdio.h>
main()
/*
Generate a table for a byte-wise 32-bit CRC calculation on the polynomial:
x^32+x^26+x^23+x^22+x^16+x^12+x^11+x^10+x^8+x^7+x^5+x^4+x^2+x+1.
Polynomials over GF(2) are represented in binary, one bit per coefficient,
with the lowest powers in the most significant bit. Then adding polynomials
is just exclusive-or, and multiplying a polynomial by x is a right shift by
one. If we call the above polynomial p, and represent a byte as the
polynomial q, also with the lowest power in the most significant bit (so the
byte 0xb1 is the polynomial x^7+x^3+x+1), then the CRC is (q*x^32) mod p,
where a mod b means the remainder after dividing a by b.
This calculation is done using the shift-register method of multiplying and
taking the remainder. The register is initialized to zero, and for each
incoming bit, x^32 is added mod p to the register if the bit is a one (where
x^32 mod p is p+x^32 = x^26+...+1), and the register is multiplied mod p by
x (which is shifting right by one and adding x^32 mod p if the bit shifted
out is a one). We start with the highest power (least significant bit) of
q and repeat for all eight bits of q.
The table is simply the CRC of all possible eight bit values. This is all
the information needed to generate CRC's on data a byte at a time for all
combinations of CRC register values and incoming bytes. The table is
written to stdout as 256 long hexadecimal values in C language format.
*/
{
unsigned long c; /* crc shift register */
unsigned long e; /* polynomial exclusive-or pattern */
int i; /* counter for all possible eight bit values */
int k; /* byte being shifted into crc apparatus */
/* terms of polynomial defining this crc (except x^32): */
static int p[] = {0,1,2,4,5,7,8,10,11,12,16,22,23,26};
/* Make exclusive-or pattern from polynomial */
e = 0;
for (i = 0; i < sizeof(p)/sizeof(int); i++)
e |= 1L << (31 - p[i]);
/* Compute and print table of CRC's, five per line */
printf(" 0x00000000L");
for (i = 1; i < 256; i++)
{
c = 0;
for (k = i | 256; k != 1; k >>= 1)
{
c = c & 1 ? (c >> 1) ^ e : c >> 1;
if (k & 1)
c ^= e;
}
printf(i % 5 ? ", 0x%08lxL" : ",\n 0x%08lxL", c);
}
putchar('\n');
return 0;
}