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TRIDAG.DEM
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1991-04-29
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2KB
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62 lines
PROGRAM d2r4(input,output,dfile);
(* driver for routine TRIDAG *)
LABEL 10,99;
CONST
np=20;
TYPE
glnarray = ARRAY [1..np] OF real;
VAR
k,n: integer;
diag,superd,subd,rhs,u: glnarray;
dfile : text;
(*$I MODFILE.PAS *)
(*$I TRIDAG.PAS *)
BEGIN
glopen(dfile,'matrx2.dat');
10: readln(dfile);
readln(dfile);
readln(dfile,n);
readln(dfile);
FOR k := 1 to n-1 DO read(dfile,diag[k]);
readln(dfile,diag[n]);
readln(dfile);
FOR k := 1 to n-2 DO read(dfile,superd[k]);
readln(dfile,superd[n-1]);
readln(dfile);
FOR k := 2 to n-1 DO read(dfile,subd[k]);
readln(dfile,subd[n]);
readln(dfile);
FOR k := 1 to n-1 DO read(dfile,rhs[k]);
readln(dfile,rhs[n]);
(* carry out solution *)
tridag(subd,diag,superd,rhs,u,n);
writeln ('the solution vector is:');
FOR k := 1 to n-1 DO write(u[k]:12:6);
writeln(u[n]:12:6);
(* test solution *)
writeln ('(matrix)*(sol''n vector) should be:');
FOR k := 1 to n-1 DO write(rhs[k]:12:6);
writeln(rhs[n]:12:6);
writeln ('actual result is:');
FOR k := 1 to n DO BEGIN
IF (k = 1) THEN BEGIN
rhs[k] := diag[1]*u[1] + superd[1]*u[2]
END ELSE IF (k = n) THEN BEGIN
rhs[k] := subd[n]*u[n-1] + diag[n]*u[n]
END ELSE BEGIN
rhs[k] := subd[k]*u[k-1] + diag[k]*u[k]
+ superd[k]*u[k+1]
END
END;
FOR k := 1 to n-1 DO write(rhs[k]:12:6);
writeln(rhs[n]:12:6);
writeln ('***********************************');
IF eof(dfile) THEN GOTO 99;
writeln ('press return for next problem:');
readln;
GOTO 10;
99: close(dfile)
END.