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- Newsgroups: sci.physics
- Path: sparky!uunet!stanford.edu!leland.Stanford.EDU!leland.stanford.edu!zowie
- From: zowie@daedalus.stanford.edu (Craig "Powderkeg" DeForest)
- Subject: Re: No Spin in 2 Dimensions?
- In-Reply-To: Richard.Mathews@West.Sun.COM's message of 12 Nov 1992 00:30:21 GMT
- Message-ID: <ZOWIE.92Nov11230652@daedalus.stanford.edu>
- Sender: news@leland.Stanford.EDU (Mr News)
- Organization: Stanford Center for Space Science and Astrophysics
- References: <92315.002515CCB104@psuvm.psu.edu> <1ds8itINN7g7@smaug.West.Sun.COM>
- Date: 11 Nov 92 23:06:52
- Lines: 25
-
- Richard.Mathews@West.Sun.COM (Richard M. Mathews) writes:
- <CCB104@psuvm.psu.edu> writes:
- >I heard it said by a former physics grad student that a certain professor
- >of his said that it is *obvious* why there is "no spin in 2 dimensions"
-
- Just taking a guess at what the professor might have meant:
-
- In QM, the commutator of any two different angular momentum operators is
- a constant times a third angular momentum operator linearly independent
- of the other two. If you have two dimensions and only two independent
- angular momentum operators, what is their commutator?
-
- In fact, in two dimensions there is only _one_ angular momentum operator --
- along the axis normal to the plane. There's nothing for it not to commute
- with, at all.
-
- Classically, which direction does the cross product, RxV, point in two
- dimensions?
-
- It doesn't point at all: only one of the three components of (the 3-D) RxV
- is ever nonzero (in 2-D), so it's best to think of it as a scalar...
- (though in 2-D relativity it probably isn't _really_ a scalar quantity;
- but then QM doesn't work too well with SR anyway...)
- --
- Craig DeForest -- astrophysicist for hire. DoD#314159; PhD#271828
-