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- From: wvenable@algona.stats.adelaide.edu.au (Bill Venables)
- Newsgroups: sci.math.stat
- Subject: Re: Is the logarithmic transformation monotonic?
- Date: 12 Nov 92 16:36:19
- Organization: Department of Statistics, University of Adelaide
- Lines: 35
- Message-ID: <WVENABLE.92Nov12163619@algona.stats.adelaide.edu.au>
- References: <1992Nov12.045820.4074@ucc.su.OZ.AU>
- NNTP-Posting-Host: algona.stats.adelaide.edu.au
- In-reply-to: mikef@dph1.health.su.OZ.AU's message of Thu, 12 Nov 1992 04:58:20 GMT
-
- >>>>> "Michael" == mikef <mikef@dph1.health.su.OZ.AU> writes:
-
- Michael> I have needed to make comparisons between variances of some random
- Michael> variable X, var(X). Specifically, I needed to know if var(X=a) >
- Michael> var(X=b). However, I was only able to compute var(lnX), and have
- Michael> made the comparison between var(ln{X=a}) and var(ln{X=b}).
-
- As it stands Michael this does not really make any sense. However if your
- question amounts to the following:
-
- "Is it true that var[log(X)] > var[log(Y)] implies var[X] > var[Y] where
- X and Y are positive random variables?"
-
- then the answer is "No, it doesn't", (even though log(x) is indeed a
- monotone increasing function for positive values of x).
-
- Just consider a simple sample case and put, say ,
-
- X = {110, 120, 130} and Y = {10, 11, 12}.
-
- Then var[X] = 100 and var[Y] = 1 so var[X] > var[Y].
-
- On the other hand var[log(X)] = .0069808 and var[log(Y)] = .008316 so
- var[log(X)] < var[log(Y)].
-
- It comes about because on the one hand var[c + X] is the same for all
- constants c, whereas var[log(c*X)] is the same for all positive constants
- c. By trading these off one against the other you can make the direction
- of the inequalities go either way.
-
- Bill
- --
- ___________________________________________________________________________
- Bill Venables, Dept. of Statistics, | Email: venables@stats.adelaide.edu.au
- Univ. of Adelaide, South Australia. | Tel: +61 8 228 5412 Fax: ...232 5670
-