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- From: mccolm@darwin.math.usf.edu. (Gregory McColm)
- Newsgroups: sci.math
- Subject: Re: A question on binary relations
- Message-ID: <1992Nov5.210728.7023@ariel.ec.usf.edu>
- Date: 5 Nov 92 21:07:28 GMT
- References: <rkaivola.720548141@mits> <1992Oct31.181604.18857@mp.cs.niu.edu>
- Sender: news@ariel.ec.usf.edu (News Admin)
- Organization: Univ. of South Florida, Math Department
- Lines: 26
-
- In article <1992Oct31.181604.18857@mp.cs.niu.edu> rickert@mp.cs.niu.edu (Neil Rickert) writes:
- >In article <rkaivola.720548141@mits> rkaivola@mits.mdata.fi (Risto Kaivola) writes:
- >> On brushing up my knowledge of discrete mathematics, I came across the
- >>following question in a book on the subject. The words inside brackets
- >>are my comments.
- >>
- >>7. Consider the equivalence relation ~ defined on Z [the set of integers]
- >> by m ~ n if m is even and n=m+1, or m is odd and m=n+1. Describe the
- >> equivalence classes. Is the natural addition well defined [natural
- >> addition having been defined earlier on]?
- >>
- >>I can't read this question in a way that would make the relation ~
- >>reflexive. Can you?
- >>In my opinion, it is not an equivalence relation at all.
- >
- >Sure, its an equivalence relation.
- >
-
- It is niether reflexive (it is NOT true that 1 ~ 1)
- nor transitive (even though 1 ~ 2 and 2 ~ 3, it is
- NOT true that 1 ~ 3). It is symmetric, and in fact
- defines the infinite graph
-
- ... --(-1)--(0)--(1)-- ... .
-
- -----Greg McColm
-