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- Newsgroups: sci.math
- Path: sparky!uunet!stanford.edu!CSD-NewsHost.Stanford.EDU!Sunburn.Stanford.EDU!pratt
- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Subject: Re: Assorted questions and problems
- Message-ID: <1992Nov9.232300.18490@CSD-NewsHost.Stanford.EDU>
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- References: <BxDJ8v.DCw@world.std.com> <1992Nov8.181631.13298@Princeton.EDU> <96778@netnews.upenn.edu>
- Date: Mon, 9 Nov 1992 23:23:00 GMT
- Lines: 27
-
- In article <96778@netnews.upenn.edu> weemba@sagi.wistar.upenn.edu (Matthew P Wiener) writes:
- >In article <1992Nov8.181631.13298@Princeton.EDU>, tao@fine (Terry Tao) writes:
- >>(3) Assume the axiom of choice and the axiom of the continuum. Is it
- >>true that two chains (totally ordered sets) which both have the
- >>cardinality of the continuum have a one-to-one and onto order
- >>preserving mapping betweem them?
- >
- >Of course not. It's almost embarrassing to mention the counterexamples,
- >but here goes: (0,1) and [0,1]. The question you meant to ask, I assume,
- >was if the orderings were dense. In that case, a back and forth argument
- >shows the two are isomorphic. I'm pretty certain you need CH for this--I
- >think Shelah has the contrary model.
-
- Actually they are not isomorphic, since only the latter has a least
- element and a greatest element.
-
- The back-and-forth argument shows that there are exactly four
- *countable* dense chains, depending on whether they have a top and
- independently a bottom. For a counterexample to the generalization of
- this to *uncountable* dense chains, remove the irrationals from the
- middle third of (0,1). In any isomorphism of that chain with (0,1),
- the middle third of the former will be paired with an *interval* of the
- latter of measure 0, which can consist only of one point, so these are
- two nonisomorphic dense uncountable chains. (One of these days I'll
- strike it lucky and get a measure-theoretic argument correct. :-)
- --
- Vaughan Pratt
-