home *** CD-ROM | disk | FTP | other *** search
- Path: sparky!uunet!stanford.edu!agate!ucbvax!ucdavis!ucdmath.ucdavis.edu
- From: brick@ucdmath.ucdavis.edu (Stephen Brick)
- Newsgroups: sci.math
- Subject: from an ad
- Message-ID: <18923@ucdavis.ucdavis.edu>
- Date: 5 Nov 92 21:39:47 GMT
- Sender: usenet@ucdavis.ucdavis.edu
- Distribution: usa
- Organization: Math department, UC Davis
- Lines: 48
-
- Recently I posted an article here which turned out to be a FAQ.
- I offer my apologies for doing so. Here is a little something
- to make up for my faq sin.
-
- In the April 18, 1986 edition of the San Francisco Chronicle,
- an ad for the video store "Adam's Video Sales" contained the
- following:
-
- Show that
-
- xgx^{-1}gx^{-1}gxgx^{-1}gx = 1
-
- where g^2=1 and g \ne 1
-
- has no solution over the group Z_2 and
- get your choice of a free telephone or
- AM/FM radio with headphones.
-
- A few words of explanation are in order. The group Z_2
- is the cyclic group of order two (here with non-trivial
- element g). The equation having a solution *over* Z_2 means
- that Z_2 is a subgroup of a bigger group that contains
- some element x which satisfies the above equation. (Of
- course, the problem is to show that no such element x
- exists in *any* group containing Z_2 as a subgroup.)
-
- The store was owned by someone with an advanced degree
- in engineering. Each week he would include an applied
- math problem and give out a free telephone or radio
- to anyone who solved the problem (I got the feeling
- that he enjoyed talking math with the people who came
- in with solutions). Of course, the offer is no longer
- valid. In fact, the store went out of business (changed
- ownership ?) a number of years ago.
-
- I was wondering if there have been any other promotions
- connected with mathematics. (Also, feel free to try
- to solve the problem.)
-
- Btw, the equation is an example due to Roger Lyndon.
-
- ----------------------------------------------------
- Steve Brick
- Dept of Mathematics
- UC-Davis
- Davis, CA 95616
-
- brick@ucdmath.ucdavis.edu
-