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- From: hrubin@pop.stat.purdue.edu (Herman Rubin)
- Subject: Re: To express Q(x)/P(x) into continued fraction
- Message-ID: <Bx98wu.Mz7@mentor.cc.purdue.edu>
- Sender: news@mentor.cc.purdue.edu (USENET News)
- Organization: Purdue University Statistics Department
- References: <1992Nov5.064414.28859@griffin.itc.gu.edu.au>
- Date: Thu, 5 Nov 1992 18:05:18 GMT
- Lines: 31
-
- In article <1992Nov5.064414.28859@griffin.itc.gu.edu.au> jchen@sct.gu.edu.au (Jinghong CHEN) writes:
-
- >Suppose there are two n-th order polynomials Q(x) and P(x), how can we
- >express Q(x)/P(x) into a continued fraction, i.e.
-
- > Q(x) a0
- > ------ = ----------------------
- > P(x) a1
- > x + -----------------
- > an
- > x + ... + ------
- > x + a
-
- >I am not sure if it is possible. Thank you in advance.
-
- As stated, it cannot be done, because Q(x)/P(x) approaches a non-zero limit
- as x -> infinity in general. So you would have to add a constant.
-
- Even in this case, it usually cannot be done, and if the last a were dropped,
- the quotient would have to be odd. You have only n+1 a's and 2n constants.
- However, for almost all such fractions, you can get the expression if
- an additive constant is allowed before each fraction. One way to do this,
- and other similar things, is by brute force; see the book by Khovanskii
- and Khovanskii. In exceptional cases, it may be necessary to use higher
- degree polynomials before each fraction. In most problems, doing it by
- brute force is about as easy as any other method.
- --
- Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399
- Phone: (317)494-6054
- hrubin@pop.stat.purdue.edu (Internet, bitnet)
- {purdue,pur-ee}!pop.stat!hrubin(UUCP)
-