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- Path: sparky!uunet!munnari.oz.au!ariel.ucs.unimelb.EDU.AU!ucsvc.ucs.unimelb.edu.au!lugb!news
- Newsgroups: sci.electronics
- Subject: Re: 12 V -> 3V, 0.6 A
- Message-ID: <1992Nov10.053522.21871@lugb.latrobe.edu.au>
- From: MATGBB@LURE.LATROBE.EDU.AU (BYRNES,Graham)
- Date: Tue, 10 Nov 1992 05:35:22 GMT
- Sender: news@lugb.latrobe.edu.au (USENET News System)
- References: <1992Nov7.141550.538@ludd.luth.se> <sehari.721280522@class1.iastate.edu>
- Organization: La Trobe University
- In-Reply-To: sehari@iastate.edu's message of Mon, 9 Nov 1992 03:42:02 GMT
- X-News-Reader: VMS NEWS 1.24
- Lines: 36
-
- In <sehari.721280522@class1.iastate.edu> sehari@iastate.edu writes:
-
- > In <1992Nov7.141550.538@ludd.luth.se> d89-ahg@ludd.luth.se (Anders Hedberg) writes:
- >
- > >A friend wants to listen to his CD player powered from the car.
- >
- > >The CD-player wanna have 3Volts at max 600 mA, and the car has a battery
- > >of 12 volts.
- >
- > >I thought of a LM317 or something similar, but I've never designed something
- > >alike, and I need to know how to calculate the resistor values.
- >
- > >/Anders Hedberg
- >
- > There are many ways to do this the cheapest way is to put:
- >
- > 12-3
- > --------- = 13 diodes in series with the input voltage of your CD player,
- > 0.7
- >
- [stuff cut]
- > --
- DONT DO THIS!!!!
- Car batteries can swing between 11.5 and 16 volts. The above will give a
- voltage ranging from 2.4 to 7 to your CD player. Worse, switching spikes
- of > 50 volts are common in car electricals, applying 41 volts (=death)
- to your CD player. (This assuming .7 volt drop across each diode,
- which is not really correct, IMHO). MUCH better to use an LM317 (simpler, too).
- Someone else has quoted the R values needed. (toss in a 220uF cap each side
- as well).
-
- You may still have problems if you want to connect the CD direct to your
- car stereo due to the way the battery negative is connected to the signal
- ground, but it will work fine for headphones (until you hit a pot-hole).
- Cheers,
- Graham Byrnes
-