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- Path: sparky!uunet!decwrl!ames!agate!doc.ic.ac.uk!uknet!cam-orl!jm
- From: dg@cam-orl.co.uk (Dave Garnett)
- Newsgroups: sci.astro
- Subject: Deflecting P/S-T
- Message-ID: <1992Nov10.145458.25432@cam-orl.co.uk>
- Date: 10 Nov 92 14:54:58 GMT
- Sender: jm@cam-orl.co.uk (Jenny Martin)
- Reply-To: dg@cam-orl.co.uk (Dave Garnett)
- Organization: Olivetti Research Ltd, Cambridge, England
- Lines: 46
-
- I was idly wondering how hard you would have to push
- something like P/Swift-Tuttle to avoid a collision, and
- came up with the following (very rough !) numbers.
-
- If P/S-T is 10km dia, sg = 3.0, then it might mass
- 1.57e15 kg
-
- In the worst case scenario, it would head straight for
- the center of the Earth, and so would require a deflection
- of about 8000km to miss.
-
- If you applied a constant thrust perpendicular to the
- track for 1 year (31e6 seconds), then the acceleration
- required from Newton is:-
-
- a = 2 . 8000 . 1000 / (31e6)^2
- = 16e-9 m/s^2
-
- Hence the force required is = mass . accel
-
- = 26e6 kgf
- = 2600 tonnes !
-
- Applying the force for longer reduces the force as the
- square of the time - thus
-
- 2 years - 650 tonnes
- 3 years - 280 tonnes
- 4 years - 162 tonnes
-
- If these numbers are correct (experts please !), that seems
- pretty difficult to do. After all, you've got to get the
- propulsion system to P/S-T, and then its got to work non-stop
- for a long period. Of course the body will almost certainly
- be tumbling, meaning that you can't just have one engine in
- a fixed position !
-
- People talk about light sails, but how big does a light sail
- have to be to produce this kind of force at a considerable
- distance from the sun ?
-
- Perhaps the answer is to do the 'correction' on the previous
- orbit, when P/S-T passes closest to the sun, and hence the
- largest source of free energy ?
-
- Dave
-