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- From: conrad@germain.harvard.edu (Keith Conrad)
- Newsgroups: sci.math
- Subject: p-adic gamma
- Message-ID: <1992Oct14.234914.16403@husc3.harvard.edu>
- Date: 15 Oct 92 03:49:13 GMT
- Article-I.D.: husc3.1992Oct14.234914.16403
- Distribution: world
- Organization: Dept. of Math, Harvard Univ.
- Lines: 36
- Nntp-Posting-Host: germain.harvard.edu
-
- p = 3, 0 <= n <= 1082, n = 9k + r with 0 <= r <= 8
- A_3(9k) = 2k
- A_3(9k + 1) = 2k
- A_3(9k + 2) = 2k
- A_3(9k + 3) = 2k + 2
- A_3(9k + 4) = 2k + 1
- A_3(9k + 5) = 2k + 3 + ord_3(2k + 1)
- A_3(9k + 6) = 2k + 2
- A_3(9k + 7) = 2k + 2
- A_3(9k + 8) = 2k + 3
-
- I have looked at A_p(n) as well for p = 5, 7, 11, 13, and 17 for
- n running up to at least 400 (in the case of 5 and 7 for n up to 1400),
- and what seems to be happening is
- A_p(n) = (p - 1)[n/p^2] + r_n, ( [ ] = greatest integer)
- where r_n >= 0 and for "most" residue classes n(mod p^2) it turns out that
- if m = n (mod p^2) then r_m = r_n. For example, when p = 2 this "mod p^2
- periodicity of r_n" occurs for all classes mod 4. When p = 3 there is
- one exception, namely the class of 5 mod 9. When p = 5 there seem to be
- (at least) four exceptions: the classes of 4, 7, 16, and 22 mod 25. When
- p = 7 I have so far found only one class mod 49 for which the n in that
- class don't have the same r_n value - it's 19 mod 49. Due to the slower
- growth of A_p(n) as p increases, there are probably some more exceptions to
- this when p = 7 which I have not located.
- Even in the (seemingly) few exceptional classes mod p^2 not admitting a
- constant r_n value, it seems that r_n = const. + s_n where the const. only
- depends on the residue class and s_n increases very slowly with n (see the data
- for p = 3 and the class of 5 mod 9).
- So what I'd like to know is if anyone can explain this behavior of
- A_p(n), ESPECIALLY the periodicity of the r_n's mod p^2. The fact that
- A_p(n) grows like (p - 1)n/p^2 seems to be due to Gamma_p(n) being locally
- analytic on cosets of pZ_p (well, for p > 2), although I haven't worked out
- the details on this.
-
- Responses can be given on this newsgroup, although I'd also appreciate it
- if they could be sent to me as well. Thanks.
-