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- Newsgroups: sci.math
- Path: sparky!uunet!comp.vuw.ac.nz!canterbury.ac.nz!math!wft
- From: wft@math.canterbury.ac.nz (Bill Taylor)
- Subject: Another chocolate fish problem.
- Message-ID: <Bw3E8p.FEn@cantua.canterbury.ac.nz>
- Nntp-Posting-Host: sss330.canterbury.ac.nz
- Organization: Department of Mathematics, University of Canterbury
- Date: Wed, 14 Oct 1992 03:41:12 GMT
- Lines: 24
-
- I'm glad to see that among all the religious proselytizing, requests for
- medical costs handouts, wood-duck comments, and *endless* debating about
- Barbie dolls, there is *still* some actual math happening in this newsgroup.
-
- Let me add to this majority interest with an easy-ish problem. As always,
- first fully correct answer may claim a chocolate fish off me personally, on
- any visit to Christchurch, New Zealand.
- ----
-
- Define u(n) = number of ordered partitions of n into 1's & 2's only.
-
- e.g. u(4) = |{ 1111 , 112 , 121 , 211 , 22 }| = 5 .
-
- Define v(n) = number of ordered partitions of n into 2's & above.
-
- e.g. v(6) = | { 6 , 42 , 24 , 33 , 222 } | = 5 .
-
- PROBLEM: prove u(n) = v(n+2) for all n.
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- Bill Taylor wft@math.canterbury.ac.nz
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- This sentence does not have the property it claims to be lacking.
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