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- Newsgroups: sci.math
- Path: sparky!uunet!brunix!brunix!dzk
- From: dzk@cs.brown.edu (Danny Keren)
- Subject: Re: Question on real numbers
- Message-ID: <1992Oct9.050302.1900@cs.brown.edu>
- Sender: news@cs.brown.edu
- Organization: Brown University Department of Computer Science
- References: <1992Oct8.211117.19295@rz.uni-karlsruhe.de>
- Date: Fri, 9 Oct 1992 05:03:02 GMT
- Lines: 17
-
- vhansen@ipfs.bau-verm.uni-karlsruhe.de (Wolfgang von Hansen) writes:
- #Hi everybody,
- #
- #is it possible to express any real number x with the following term
- #
- #x = a + rb; a, b \in Q; r \in R, r const.
-
- That is impossible, as such a set is countable, hence cannot
- be equal to R. It will simply span a 2D sub-space of R (if r
- is irrational). Now, R is a vector space over Q, and hence
- (if one allows the axiom of choice) have a basis, but that basis
- has much more than two elements. The existence of such a basis
- allows to construct interesting counter examples, such as a
- function f:R--->R satisfying f(a+b)=f(a)+f(b) where f is not linear.
-
- -Danny Keren.
-
-