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- Path: sparky!uunet!europa.asd.contel.com!darwin.sura.net!convex!news.utdallas.edu!corpgate!bnrgate!bmerh85!bcrki9!mkfeil
- From: mkfeil@bcrki9.bnr.ca (Max Feil)
- Subject: Radio Interference (technical)
- Message-ID: <1992Sep14.210450.4479@bmerh85.bnr.ca>
- Sender: news@bmerh85.bnr.ca (Usenet News)
- Organization: Bell-Northern Research
- References: <1992Sep04.182848.22823@bmerh85.bnr.ca> <1992Sep09.172231.9024@bmerh85.bnr.ca>
- Date: Mon, 14 Sep 92 21:04:50 GMT
- Lines: 211
-
- Here is a great technical description of the issues being discussed in a
- related thread. It was not written by me.
-
-
- From: 'galaxy.nsc.com!pad@gatech.uucp'
- Subject: Radio interference
-
- Max,
-
- I have read your posting and appreciate your efforts to explain the problems
- people have with R/C gear, however I feel that while some of the conclusions
- are correct some are not and the explanations are not really accurate. I know
- that you are not an RF engineer so please do not take this as a flame - I work
- as an RF engineer and have attempted to explain my view of what is going on
- and I hope you will find the following constructive. If this email generates
- questions on your behalf please feel free to email me.
-
- RADIO COMPONENTS
-
- To understand what is happening in a radio you need to understand what the
- following components do;
-
- filters; These are devices that only allow certain frequencies to pass through.
- In a radio they are almost always bandpass filters and can roughly be
- specified as having a centre frequency and a bandwidth. The ideal filter
- (which can be proven not to be realisable) would allow the frequencies within
- the bandpass to pass through the filter with no attenuation and stop all
- other frequencies from passing through at all. Real filters pass most of the
- signal at the centre frequency and gradually reduce the amplitude of the
- signal as the frequency moves further away from the centre frequency. Filters
- can be made to approach the ideal filter but the closer you get the heavier
- bigger and more expensive they become. As filters approach this ideal they are
- said to have a higher order. It turns out that for a given order, a filter will
- have a narrower bandwidth if its centre frequency is lower (remember this as it
- will explain why we have frequecy conversions in radios later). So if a filter
- that is small light and cheap has bandwidth of 350khz and centre frequency
- of 72MHz an equivalent order filter at 10.7MHz will have a bandwidth of 53Khz
- and at 455KHz a bandwidth of 2KHz. So *filters are easier to make narrowband
- at low frequencies*
-
- mixers; An ideal mixer takes two input signals and multiplies them to give its
- output. This is all they do. Real mixers will introduce gain or loss and more
- importantly for this discussion introduce distortion. This distortion
- characteristic can be described as a power series so that for an input x the
- output will contain (a0 + a1.x + a2.x^2 + a3.x^3 + ....) a0 is the dc offset
- at the output a1 is the linear gain a2 is the coefficient for 2nd order
- distortion which will produce 2IM a3 is the coefficient for 3IM. The co-
- efficients usually decrease very rapidly but the higher power terms increase
- faster with increasing x (amplitude) so that (if the gain does not compress)
- the 2nd and 3rd order terms eventually exceed the linear term. The smaller the
- coefficients of the higher order terms are the more linear the radio is - this
- is good for preventing distortion but often bad for increasing noise so mixer
- designers try to compromise.
-
- amplifiers; Ideal amplifiers just amplify signals - real ones introduce
- distortion - see above
-
- Radio Receivers
-
- The big problem that your airplane has is to know which transmitter to
- listen to - at the aerial *every* radio transmission is present - other R/C
- channels, pagers, local radio stations, t.v., C.B. etc etc. The receiver tries
- to achieve this by by using filters to remove everything except the frequency
- band that you are transmitting on. The simplest way to do this would be to
- put a filter directly after the aerial that stopped everything but your
- transmission band. Your signal could then be amplified and demodulated with no
- further ado. This type of radio is called a tuned radio frequency reciever
- or TRF for short. This is such a simple idea - why don't more people use it?
- Well for the fllowing reasons;
-
- i) The filter would have to be 20KHz wide at 72MHz which requires a very
- expensive high order filter.
-
- ii)All amplification and demodulation needs to be done at high frequency which
- requires high power consumption circuitry.
-
- To get around this problem radios use either one intermediate frequency ("if")
- and are called heterodyne receivers or more than one (usually two) in which
- case they are called superheterodyne receivers (superhet for short).
-
- Heterodyne receivers (single conversion receivers)
-
- Heterodyne recevers work like this; All signals go into the aerial and a low
- order filter selects frequencies +/- about 600khz either side of the centre
- of the R.C. band. This filter is called the image filter and you should note
- that it allows *all* the R/C channels through (yes I know! read on...).
- They then go to a mixer which multiplies all the incoming signals by the
- crystal frequency of the receiver (called the local oscillator with frequency
- "flo"). For every input frequency "fs" to the mixer the output contains ;
-
- fout = fs*flo
-
- As you said it can be shown by trigonometry theory that;
-
- cos(2*pi*flo*t)*cos(2*pi*fs*t)=1/2*( cos(2*pi*(flo-fs)*t)+cos(2*pi*(flo+fs)*t)
-
-
- or the output of the mixer contains frequencies at flo-fs and flo+fs. Now the
- output of the mixer is put through a filter with a centre frequency at 455KHz
- and a bandwidth of 20KHz (this is called the channel select filter). This
- definitely gets rid of the flo+fs terms as they are up at about 144MHz but
- what gets through? well anything that satisfies the relationship;
-
- flo-fs=+455KHz **or** flo-fs=-455KHz
-
- you may well say what does -455KHz mean? - It is called the image frequency
- and is actually a positive frequency the same as +455KHz but phase inverted
- by 180 degrees (or multiplied by -1 if you prefer).
-
- to select your transmission frequency the receiver crystal is designed so
- that flo-fs=+455KHz so flo=fs+455KHz however if the input of the mixer
- has a frequency at flo+455KHz (which is fs+910KHz) then you will get an
- interference output frequency at 455KHz. You rely on the image filter
- (see above) to reject this frequency *before* it gets to the mixer
- (once it gets into the mixer there is nothing you can do about it)
- however this filter has to be at least as wide as the R/C spectrum
- which is channel spacing*number of channels (I think there are
- 60 channels now? so the image filter is then 1200kHz wide) so a single
- conversion receiver can let frequencies 45.5 channels away interfere. whether
- the interfering channel is 45.5 channels above or below your channel will
- depend whether your receiver uses high side or low side flo injection (this
- just means whether flo=fs+455Khz or flo=fs-455KHz respectively). If all
- receivers used high side injection then channels 45.5 above you would interfere
- with you but you would not interfere with them. For high side injection
- receivers you want to be one of the high frequency channels, for low side
- injection receivers you want to be one of the low frequency ones.
-
- This effect has nothing to do with 2nd order intermodulation it is due to
- a lack of image rejection in single conversion receivers.
-
- 2IM
-
- As we have seen - any signals at 455KHz coming out of the mixer get through
- the channel select filter. If the mixer circuitry has 2nd order distortion
- (a2*x^2) then an input of a + b will be distorted to a^2 + a*b + b^2
- the square terms of this quadratic can be ignored (they are easy to filter)
- so that the effect of 2IM is to multiply input signals together which are
- then multiplied by the local oscillator. the effect of this is that large
- signals 455KHz apart at the input to the mixer generate 455KHz at the *input*
- to the mixer -whether these get to the output and cause interference depends
- on the mixer type - a good balanced mixer will attenuate these signals before
- to the output.
-
- In summary a single conversion R/C radio will always have poor image rejection
- and if the image frequency is inside the band of the image filter 910KHz
- away from your channel you will get interference. 2IM may or may not be a
- problem if the mixer has either low 2nd order distortion or is well balanced
- or both then 2IM will be less of a problem. 2IM becomes a problem when the
- two interfering signals are strong and your signal is weak.
-
-
- Superhet receivers (dual conversion)
-
- These have 2 intermediate frequencies. The first mixer now has an output
- image frequency 21.4MHz away (2*10.7MHz) these are easily filtered by the
- image filter between the aerial and the first mixer. 2IM products need to
- be 10.7MHz apart and these are similarly easily filtered by the image filter.
- So now all we do is filter at 10.7MHz and detect our signal right? well if
- the filter you used was 20KHz wide then yes you could do this but such filters
- are expensive and the circuitry at 10.7MHz still requires fairly high power.
- So a superhet filters at 10.7MHz with a cheap filter that is about 100khz
- wide. After this filter you simply mix the signal with a local oscillator
- whose frequency is fs+455KHz (sound familiar?) the output is filtered at 455KHz
- with a bandwidth of 20khz to select your signal the image frequency at this
- if is 910KHz but the filter at 10.7MHz has removed it - so no interference
- from images or 2IM.
-
- Can anything interfere with superhets then? Yes ;
-
- If a transmitter transmits on your frequency it will fairly obviously
- interfere if its strong enough. The interfering signal must be substantially
- higher to interfere with an fm system than an am system (this applies to any
- of the interferers listed above or below which is why fm systems are less
- prone to interference - all else being equal). This situation will arise if:
-
- i) Someone transmits on the same frequency as you
-
- ii) Someone transmits on a frequency close to you with a wideband transmitter
- (if his transmitter bandwith is 60KHz some of his signal will spill into
- your channel if enough energy spills ....)
-
- iii) 3IM ; the mechanism for this is identical to 2IM but now the cube of
- the two input signals generate 2f1-f2 and 2f2-f1 ( simply look up the
- trig for (cos a + cos b)^3 ) if two channels are spaced xHz and 2*xHz
- away from you 3IM in the first mixer will produce an interferer at
- the same frequency as you - it cannot be filtered once produced.
- the image filter will not be able to remove these as they can be
- any of other RC channels with the correct spacing (note the image
- filter must allow all the channel through or you would not be able
- to use all the channels (crystals) available in any set which would
- be a production nightmare.
-
- A final mechanism for interference is jamming whereby the radio is simply
- overloaded by a *very* strong signal that gets through the image filter-
- it simply overloads the circuitry.
-
-
- I hope you find this of some value - I may have made some errors (after all
- I'm only human!) but I think its mostly correct and if you disagree with
- any of it or have any questions I will be happy to answer them.
-
- Cheers - Paul
-
-
-
-
- --
- Max Feil mkfeil@bnr.ca | Disclaimer:
- Bell-Northern Research | What do I know? I'm just a Nerd on the Big Ranch.
- P.O Box 3511 Station C, |
- Ottawa, Ontario, Canada.| "Enrich The Soil, Not EveryBody's Goal" Peter Gabriel
-