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- From: tomb@hplsla.hp.com (Tom Bruhns)
- Date: Thu, 10 Sep 1992 16:26:18 GMT
- Subject: Re: Inverting buffer?
- Message-ID: <5070312@hplsla.hp.com>
- Organization: HP Lake Stevens, WA
- Path: sparky!uunet!elroy.jpl.nasa.gov!sdd.hp.com!hp-cv!hp-pcd!hplsla!tomb
- Newsgroups: rec.audio
- References: <1992Sep10.012158.5817@cbnews.cb.att.com>
- Lines: 38
-
- wkb@cbnews.cb.att.com (wm.keith.brummett) asks,
-
- > can one make a similar unity-gain INVERTING buffer?
-
- Yep, but you _do_ have to use resistors. Simply put resistors in the input
- and feedback paths.
- R2
- ____/\/\/\____
- | __ |
- In __/\/\/\____|____| \ |
- R1 | - \____|____ Out
- ____| + /
- _|__ |__/
- ///
-
- > I can't seem to find any example of such an inverting buffer anywhere
- > (one using no resistors, that is). And, a Radio Shack engineering book
- > claims that with the resistors, the gain is (1 + R2/R1), whereas the
- > gain of the similar non-inverting buffer is just (R2/R1). If this is
- > true, how does one make a unity-gain, inverting buffer?
-
- Actually, the gain of the inverting buffer is -R2/R1. It's true; if
- you ground what's labeled "in" and feed the signal into the + op amp
- input, then the gain is 1+R2/R1. So if R2=R1, you get unity gain
- as an inverting amp and gain-of-2 as non-inverting. You can get gain-
- of-one non-inverting from it by feeding the + input with a voltage
- divider, two equal-valued R's.
-
- Burr-Brown sells an INA105 that packages all this up in a single 8-pin
- package (DIP or SOIC); it's called a unity gain differential amplifier.
- You can ground either input, feed the signal into the other, and get out
- either the signal or -1* the signal.
-
- If you want to really accurately switch between + and - with the same
- gain, the R's have to be matched quite well. I have a trick that
- reduces the matching requirement, but only if you are willing to
- accept gain in the stage.
-
-