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- Newsgroups: comp.parallel
- Path: sparky!uunet!cis.ohio-state.edu!magnus.acs.ohio-state.edu!usenet.ins.cwru.edu!gatech!hubcap!fpst
- From: av2@ukc.ac.uk (A.Varshneya)
- Subject: Re: Synchonizing watches
- Message-ID: <1573@eagle.ukc.ac.uk>
- Sender: fpst@hubcap.clemson.edu (Steve Stevenson)
- Reply-To: av2@ukc.ac.uk (A.Varshneya)
- Organization: Computing Lab, University of Kent at Canterbury, UK.
- References: <1992Sep3.123226.14205@hubcap.clemson.edu> <1992Sep4.174143.13747@hubcap.clemson.edu>
- Date: 5 Sep 92 08:56:57 GMT
- Approved: parallel@hubcap.clemson.edu
- Lines: 17
-
-
- In article <1992Sep4.174143.13747@hubcap.clemson.edu> mln@sunkj.larc.nasa.gov (Michael L Nelson) writes:
- >A:
- >1. says "Bong"
- >2. waits, say N minutes (N > ABBA)
- >3. says "Bong" again
- >
- >B already knows what N is, and can then determine
- >What AB is (Bong2 - Bong1 - N)
-
- B will hear Bong2 and Bong1 with a gap of N minutes between them.
- ie. Bong2 = Bong1 + N. So B can not find AB.
-
- >Michael Nelson
-
- Atul
-
-