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  1. Path: sparky!uunet!know!mips2!news.bbn.com!usc!rpi!uwm.edu!psuvax1!psuvm!sxw103
  2. From: SXW103@psuvm.psu.edu (S. Wukovitz)
  3. Newsgroups: sci.math
  4. Subject: Re: A Math Induction Problem
  5. Message-ID: <92243.010704SXW103@psuvm.psu.edu>
  6. Date: 30 Aug 92 05:07:04 GMT
  7. References: <17pjpeINNouf@matt.ksu.ksu.edu>
  8. Organization: Penn State University
  9. Lines: 13
  10.  
  11. In article <17pjpeINNouf@matt.ksu.ksu.edu>, bubai@matt.ksu.ksu.edu
  12. (P.Chatterjee) says:
  13. >Then, (k+1)^3 + 5(k+1) = k^3 + 5k + 3k^2 + 3k + 6
  14. >                       =6p + 6[(1/2)k^2 + (1/2)k + 1]
  15. >Does that make sense? Or, are 1/2 's disallowed?
  16.  
  17. Whether k is even or odd, k^2 + k is even, so there is
  18. no problem here.
  19.  
  20. Hope it helps.
  21.  
  22. -Stephanie Wukovitz
  23. steph@math.cornell.edu
  24.