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- From: cxm7@po.CWRU.Edu (Colin Mclarty)
- Newsgroups: sci.logic
- Subject: Re: ZFC+~Con(ZFC)
- Message-ID: <1992Aug27.154627.3228@usenet.ins.cwru.edu>
- Date: 27 Aug 92 15:46:27 GMT
- Article-I.D.: usenet.1992Aug27.154627.3228
- References: <7160@charon.cwi.nl> <1992Aug20.171630.18667@ariel.ec.usf.edu>
- Sender: news@usenet.ins.cwru.edu
- Reply-To: cxm7@po.CWRU.Edu (Colin Mclarty)
- Organization: Case Western Reserve University, Cleveland, OH (USA)
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-
- In a previous article, jrk@sys.uea.ac.uk (Richard Kennaway) says:
-
- >In article <1992Aug20.171630.18667@ariel.ec.usf.edu> Gregory McColm,
- >mccolm@darwin.math.usf.edu. writes:
- >>The standard (ie, wellfounded) models all satisfy Con(ZFC)
- >
- >Can someone clarify for me the term "standard model"? Is this a concept
- >with a formal definition, or is a "standard model" of a theory, simply a
- >model which satisfies the intuitions which inspired the axioms of the
- >theory?
- >
- >--
- >Richard Kennaway SYS, University of East Anglia, Norwich NR4 7TJ, U.K.
- >Internet: jrk@sys.uea.ac.uk uucp: ...mcsun!ukc!uea-sys!jrk
- >
-
- I do not know what all "standard" might mean, but in a lot of
- contexts including this one it means "not non-standard" where "non-
- standard" is used as in "non-standard analysis". In short, a model is
- "standard" in this sense if all the sets it takes to be finite are
- actually finite.
-
- If a model is standard in this sense then all the sets it takes
- as codes for proofs of ZF actually are such codes, and so there is no set
- taken as coding a proof ofa contradiction, so the model satisfies Con(ZF).
- Of course all of this assumes there are models in the first place, so ZF
- is consistent. As a previous poster said, models of ZF+not-Con(ZF) are
- just models that recognize some sets as codes for proofs of contradictions.
- But what these sets code are not really finite proofs--i.e. are not
- proofs at all.
-
-
-
-