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- Newsgroups: sci.electronics
- Path: sparky!uunet!elroy.jpl.nasa.gov!usc!newshub.sdsu.edu!chemteca.sdsu.edu!massoud
- From: massoud@chemteca.sdsu.edu (Massoud Ajami)
- Subject: Re: how do you figure out cost per kilowatt-hour?
- Message-ID: <massoud.77.715362150@chemteca.sdsu.edu>
- Summary: need for figure out costs for power consumption
- Lines: 35
- Sender: news@newshub.sdsu.edu
- Nntp-Posting-Host: 130.191.227.22
- Organization: San Diego State University
- References: <124@kc2wz.bubble.org>
- Distribution: na
- Date: Tue, 1 Sep 1992 15:42:30 GMT
-
- In article <124@kc2wz.bubble.org> bob@kc2wz.bubble.org (Bob Billson) writes:
- >From: bob@kc2wz.bubble.org (Bob Billson)
- >Subject: how do you figure out cost per kilowatt-hour?
- >Summary: need for figure out costs for power consumption
- >Date: 31 Aug 92 20:28:42 GMT
- >I need to determine how much some particular electronic is costing me to run.
- >For the sake of example, I need to know the cost of running something consuming
- >100 watts, all day long, all month long. I know the cost the power company
- >charges per kilowatt-hour. Can someone provide an equation to convert the
- >equipment's power rating to kilowatt-hours?
- >
- >Simply using:
- >
- > (power_rating/1000) * hours_used * days_used
- >
- >does not work out correctly (or so it seems). Help? :-) Thanks
- >
- > Bob
- >--
- > Bob Billson, KC2WZ | internet: bob@kc2wz.bubble.org
- > | kc2wz@amsat.org
- > $nail: 21 Bates Way, Westfield, NJ 07090 | uucp: ...!uunet!kc2wz!bob
- > C code. C code run. Run code run...<please!>
-
- Equipment power rating is Watt-hour, so kilowatt-hour is watt-hour/1000.
- Of course this is for resistive loads like light bulb, iron, toaster,....
-
- (power-rating/1000) * hours_used * cost $/kwatt-hour =total cost $.
-
- units: kwatt * hour * $/kwatt-hour = $.
-
-
-
- Peace and Prosperity!
- ---==< 110 >==---
-