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- Newsgroups: comp.parallel
- Path: sparky!uunet!gatech!hubcap!fpst
- From: masticol@cadenza.rutgers.edu (Steve Masticola)
- Subject: Re: Synchonizing watches
- Message-ID: <1992Sep4.121531.18515@hubcap.clemson.edu>
- Sender: fpst@hubcap.clemson.edu (Steve Stevenson)
- Organization: Rutgers Univ., New Brunswick, N.J.
- References: <1992Sep3.123226.14205@hubcap.clemson.edu> <1992Sep3.201927.25562@hubcap.clemson.edu>
- Date: 3 Sep 92 22:52:38 GMT
- Approved: parallel@hubcap.clemson.edu
- Lines: 18
-
-
- leo@nas.nasa.gov (Leo Dagum) writes:
-
- 4) A times the first call back, and now knows (AB + BA), when he gets
- the second call back, he now knows BA as well (and therefore AB).
-
- I don't see how A will know BA from the second call... Call d the time
- difference between when b makes the first call and the second call. A
- receives the second call at time T + AB + BA + d. A knows AB + BA, T,
- and d. But A would have to know AB or BA independently to separate the
- two.
-
- Leo Dagum
- NASA Ames Reseach Center
-
- - Steve Masticola (masticol@cs.rutgers.edu)
-
-
-