home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.math.symbolic
- Path: sparky!uunet!usc!cs.utexas.edu!sdd.hp.com!mips!mips!munnari.oz.au!uniwa!cujo!marsh!pete
- From: pete@marsh.cs.curtin.edu.au (Pete Staples)
- Subject: Maple question.
- Message-ID: <pete.714023792@marsh>
- Sender: news@cujo.curtin.edu.au (News Manager)
- Organization: Curtin University of Technology
- Date: Mon, 17 Aug 1992 03:56:32 GMT
- Lines: 20
-
-
- 1/2 1/2
- Pi erf(x s) ln(lmbda)
- ans := limit exp(x) (1/2 ---------------------------
- s -> infinity 1/2
- x
-
- I am having problems with the following type of expression.
-
- I have written a procedure that uses Laplaces' method to solve integrals.
- Maple gives me an integral representation of the answer if I
- enter the limits (s=0..infinity) in the int procedure. If I evaluate
- the indefinite integral and use subs for each limit of integration
- it still doesn't evaluate the answer, eg leaves it in terms of
- erf(0), erf(x*infinity). Is there anyway that x > 0 can be assumed
- in the expression, so expressions like erf(x*infinity) can be interpreted?
-
- Hope this makes sense, thanks in advance..
-
- Peter.
-