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- Newsgroups: sci.math
- Path: sparky!uunet!news.smith.edu!orourke
- From: orourke@sophia.smith.edu (Joseph O'Rourke)
- Subject: Re: Mapping points in space to a plane
- Message-ID: <1992Aug20.192010.18892@sophia.smith.edu>
- Organization: Smith College, Northampton, MA, US
- References: <BtAIpG.5pL@wpi.WPI.EDU>
- Distribution: usa
- Date: Thu, 20 Aug 1992 19:20:10 GMT
- Lines: 19
-
- In article <BtAIpG.5pL@wpi.WPI.EDU> jac@cs.WPI.EDU (Jeffrey A Choate) writes:
- >One suggestion is to find the orthogonal projection
- >of the point on the plane. Another suggestion is to
- >use the normal to the plane (1,1,1), and starting at
- >the point follow the normal vector back until it
- >intersects the plane, and use the intersection point.
-
- I believe the second suggestion is equivalent to the first.
-
- >Are any of these ideas good?
-
- Depends on what properties you desire for your projection.
-
- >Is there an algorithmic way of doing this?
-
- If your point is (a,b,c), you want (a,b,c) + t(1,1,1) to lie on
- the plane. So (a+t) + (b+t) + (c+t) = 1, which implies that
- t = [1 - (a+b+c)]/3. So, e.g., the point (a,b,c) = (2,3,5) leads
- to t = -3, mapping to (-1,0,2).
-