home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.math
- Path: sparky!uunet!wri!news
- From: roach@bikini.wri.com (Kelly Roach)
- Subject: u(v^n)w prime puzzle - HINTS
- Message-ID: <1992Aug19.194149.24353@wri.com>
- Sender: news@wri.com
- Nntp-Posting-Host: bikini.wri.com
- Organization: Wolfram Research, Inc.
- Date: Wed, 19 Aug 1992 19:41:49 GMT
- Lines: 47
-
-
-
-
- Prove or disprove: There are three non-empty
- strings of digits u,v,w such that all the
- numbers in
- L = {u(v^n)w | n is a natural number}
- = {uw, uvw, uvvw, uvvvw, uvvvvw, ...}
- are prime numbers.
-
-
- HINT TIME!!!
-
- This is the puzzle I posted Monday. Today I'll
- give out some hints. On Friday, I'll explain the
- solution if I can't get anyone to solve the problem
- before then.
-
- HINTS:
-
- (1) Fermat's Little Theorem says
-
- c^(p-1) = 1 (mod p)
-
- if p is prime and (c,p)=1.
- (2) Let a=|v|=length of v, b=|w|=length of w.
- Then
-
- u(v^n)w = u*10^(a*n+b) + v*Sum[10^(a*i+b),{i,0,n-1}] + w
-
- Consider the two pieces
-
- u*10^(a*n+b) + w
-
- v*Sum[10^(a*i+b),{i,0,n-1}]
-
- separately.
- (3) If prime number p does not divide 10, then
-
- 10^(a*i+b) (mod p)
-
- is a periodic function of i.
- (4) If uw is not a prime, there is not much to prove.
- Might as well assume uw is a prime number.
-
-
-
-