home *** CD-ROM | disk | FTP | other *** search
- Path: sparky!uunet!wupost!uwm.edu!rpi!zaphod.mps.ohio-state.edu!uunet.ca!canrem!dosgate![ian.tuck@canrem.com]
- From: "ian tuck" <ian.tuck@canrem.com>
- Newsgroups: sci.math
- Subject: please help!!!
- Message-ID: <1992Aug18.869.11155@dosgate>
- Date: 18 Aug 92 20:33:35 EST
- Reply-To: "ian tuck" <ian.tuck@canrem.com>
- Distribution: sci
- Organization: Canada Remote Systems
- Lines: 21
-
- Hi all. My first post here. I have a problem I would like a computer
- to solve, but can't seem to find a solution. The problem is as follows
- I wish to find out the most efficient solution to the following:
- I have a box 20'X8'X8'. I have other boxes of various dimensions.
- If I have three types of boxes: 1) 1'x1'x1', 2) 2'x1'x1', and 3) 2'x2'x2'
- how do I determine a method for filling up the large box with a number of
- the smaller boxes with minimum volume left over. There may be a restraint
- (i.e. minimum 10 of box 1 type, 20 of box 3 type, any # of box 2 type).
- I tried solving this problem with Excel using the solver and volumes, but
- of course the volumes I calculated don't actually take into account
- dimensions, (i.e the volume & the dimensions matter, so that no box sticks
- out the top of the larger box). Is there anyone out there who can give me
- some method by which I can calculate this? I understand calculus, but
- couldn't come up with the minimax equations either. Thanks in advance.
-
- Ian
- ---
- ■ DeLuxe²/386 1.25 #8528 ■
- --
- Canada Remote Systems - Toronto, Ontario/Detroit, MI
- World's Largest PCBOARD System - 416-629-7000/629-7044
-