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- From: columbus@strident.think.com (Michael Weiss)
- Newsgroups: sci.math
- Subject: space-eating curves: correction
- Date: 17 Aug 92 09:33:08
- Organization: Thinking Machines Corporation, Cambridge MA, USA
- Lines: 24
- Distribution: sci
- Message-ID: <COLUMBUS.92Aug17093308@strident.think.com>
- References: <COLUMBUS.92Aug14165116@strident.think.com>
- NNTP-Posting-Host: strident.think.com
- In-reply-to: columbus@strident.think.com's message of 14 Aug 92 16:51:16
-
-
- I wrote:
-
- Topologically, H [the Hilbert cube, I^{aleph_null}] is the product of
- countably many copies of I with the product topology. Equivalently, for
- x in R^{aleph_null}, define ||x|| to be sqrt(sum (x_i)^2) (setting ||x||
- = infinity of course if the series diverges; otherwise this is the usual
- l^2 norm); then sets of the form N_e(x) = {y : ||y-x|| < e} form a
- neighborhood base (with e>0, of course.)
-
- What was I thinking? This "norm" gives a finer topology than the product
- topology. (A neighborhood base for H with the product topology consists of
- products of the form {Product A_n | n=1 to infinity}, where all A_n are
- subintervals of I open in I, and all but finitely many A_n equal I. Here
- I=[0,1]. No such product can be a subset of the set N_1(0) defined above,
- for example.)
-
- This fallacious remark was really parenthetical to the main point of my
- post, but for the record, what I had in mind was the fact that H is
- metrizable. A correct formula for a suitable metric is:
-
- d(x,y) = sqrt {sum ((x_n - y_n)/n)^2 | n=1 to infinity}
-
- where x = (x_1,x_2,...) and y = (y_1,y_2,...)
-