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- From: proberts@informix.com (Paul Roberts)
- Newsgroups: sci.math
- Subject: Re: Is Card(R)=Card(R^2)?
- Message-ID: <1992Aug13.011522.11161@informix.com>
- Date: 13 Aug 92 01:15:22 GMT
- References: <1992Aug12.102140.5231@nntp.hut.fi> <1992Aug13.000928.12631@unidus.rz.uni-duesseldorf.de>
- Sender: news@informix.com (Usenet News)
- Organization: Informix Software, Inc.
- Lines: 22
-
- In article <1992Aug13.000928.12631@unidus.rz.uni-duesseldorf.de> heisen@convex.rz.uni-duesseldorf.de (Henner Eisen) writes:
- >In article <1992Aug12.102140.5231@nntp.hut.fi> samu@lammio.hut.fi writes:
- >>I have been wondering... It seems first that there are more pairs of
- >>real numbers than real numbers, but is it really so? And if not, I would
- >>like to see a bijective mapping f:R->R^2. ...
- >
- >Such mappings exist! To construct a mapping f(x,y) = z choose a
- >unique decimal representation of x and y and then merge the digits.
- >
- >i.E.:
- >x = 1 0 0 2. 7 1 8 2 8 2 . . . . . .
- >y = 3 0 3 .1 4 1 5 9 3 . . . . . .
- >
- >z = 1300032.174118529832............
- >
- >This will be bijective for non-negative real numbers. In order to obtain a
- >bijective mapping R <-> R^2 this has to be combined with a bijection
- >which maps real numbers to non-negative real numbers (right now, I
- >don't remeber by heart how this is done, but it is possible).
-
- I believe that there is even an everywhere-continuous
- bijective mapping from the unit line to the unit square.
-