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- Path: sparky!uunet!wupost!waikato.ac.nz!canterbury.ac.nz!math!wft
- Newsgroups: sci.logic
- Subject: Re: Non-standard integers.
- Message-ID: <1992Aug19.172922.410@csc.canterbury.ac.nz>
- From: wft@math.canterbury.ac.nz (Bill Taylor)
- Date: 19 Aug 92 17:29:20 +1200
- References: <1992Aug17.141017.373@csc.canterbury.ac.nz> <16npkvINNjlq@agate.berkeley.edu>
- <1992Aug18.133344.385@csc.canterbury.ac.nz> <16rh2nINN6og@agate.berkeley.edu>
- Distribution: world
- Organization: Department of Mathematics, University of Canterbury
- Nntp-Posting-Host: math.canterbury.ac.nz
- Lines: 23
-
- > Kemeny's conjecture is false: If M is a non-standard model of
- >PA, then there is a non-standard integer n such that no integer in the
- >"standard row" of n is divisible by all standard integers.
- >
- > To see this, take n which is odd but is divisible by all
- >standard odd integers. If m differs from n by a standard integer, then
- >there must be a standard odd prime which does not divide the
- >difference. Hence m is not divisible by that prime.
-
- Looking at this bit...
-
- >take n which is odd but is divisible by all standard odd integers.
-
- ...at first it wasn't clear to me that every nonstandard model would have
- such an n . But I suppose this can be seen by taking any odd nonstandard k,
- and forming n = k(k-2)(k-4)(k-6)..... .
-
- Presumably this operation can be made legitimate in some simple way ?
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- Bill Taylor wft@math.canterbury.ac.nz
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- Kleeneness is next to Godelness.
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-