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- Path: sparky!uunet!ogicse!plains!news.u.washington.edu!milton.u.washington.edu!whit
- From: whit@milton.u.washington.edu (John Whitmore)
- Newsgroups: sci.electronics
- Subject: Re: CMOS Oscillator
- Message-ID: <1992Aug20.235204.25395@u.washington.edu>
- Date: 20 Aug 92 23:52:04 GMT
- Article-I.D.: u.1992Aug20.235204.25395
- References: <1992Aug18.140051.10073@donau.et.tudelft.nl>
- Sender: news@u.washington.edu (USENET News System)
- Organization: University of Washington, Seattle
- Lines: 60
-
- In article <1992Aug18.140051.10073@donau.et.tudelft.nl> elmar@dutentb.et.tudelft.nl (Elmar van Ginneken) writes:
-
- >What I am looking for is a low power oscillator (<.5 mA @ 5V) running
- >at a frequency of roughly 1 MHz.
- >However, the frequency-determining component should be an inductor with
- >a value of approx. 75 uH. (YES, I'm trying to measure inductance-change..)
-
- You can make an RL oscillator with a CMOS Schmitt trigger
- gate; the time constant is L/R, so your 75 uH inductor will
- require about a 470 ohm resistor. That would draw too
- much current, so try:
-
-
- +5---------VVVVV--+---VVVVV---GND
- |
- +---VVVVV--+
- | |
- - +----<Lx>----+
- - | |\ |
- | +-| >O-------+
- GND |/
-
- with the two top resistors circa 10k ohms, and the capacitor
- 1uF (preferably ceramic). The current from the inverter (a 74HC14
- would be best) will come to about 2 mA AC; it would be prudent
- to use several inverters in parallel to generate this much
- current. You get six to a package, so:
-
-
- |\ |\ |\
- -----| >O---| >O-+-| >O--+
- |/ |/ | |/ |
- | |
- | |\ |
- +-| >O--+
- | |/ |
- | +------
- | |\ |
- +-| >O--+
- | |/ |
- | |
- | |\ |
- +-| >O--+
- |/
-
- will be the full 'expansion' of the inverter.
-
- The problem here is that the current drain will come to nearly
- three mA; without using an oscillator that has a lower threshold
- voltage than CMOS Schmitt triggers, the inductors you are using
- cannot achieve oscillation at these frequencies with the 0.5 mA
- current you require.
-
- So, you will want to raise the resistance, thus lowering
- the frequency (to one kHz or so), and use a PLL to generate
- a tracking 1MHz signal; this requires three more IC's, a 74HC4046
- for the PLL and two MC14520's for the dividers (or perhaps one
- 4060 or 4020 or 4040 for the divider).
-
- John Whitmore
-