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- Path: sparky!uunet!cs.utexas.edu!swrinde!mips!news.cs.indiana.edu!news.nd.edu!tolstoy.helios.nd.edu!sremis
- From: sremis@tolstoy.helios.nd.edu (steve remis)
- Newsgroups: comp.robotics
- Subject: Re: PUMA-560 ARM _ singular points
- Keywords: PUMA,SINGULAR POINTS
- Message-ID: <1992Aug14.170745.337@news.nd.edu>
- Date: 14 Aug 92 17:07:45 GMT
- References: <1992Aug12.171255.13584@morgan.ucs.mun.ca>
- Sender: news@news.nd.edu (USENET News System)
- Reply-To: sremis@tolstoy.helios.nd.edu (steve remis)
- Organization: University of Notre Dame, Notre Dame
- Lines: 33
-
- In article <1992Aug12.171255.13584@morgan.ucs.mun.ca>, raghu@morgan.ucs.mun.ca (Raghu B) writes:
- |> Can any one tell me any reference books are any valuable materials,
- |> from where I can find the singular points for a PUMA-560 arm.
- |> I know that they are the extreme ends of the workspace. But
- |> I don't know how to find those values. Is there any algorithm
- |> or any set of equations which can be solved to get those arm
- |> joint angles theta1, theta2 and theta3.
- |>
- |> Any kind of help is highly appreciated.
- |>
- |>
- |> Raghu .B
-
-
- There are singularities which occur at the limits of the workspace. These
- values occur when sin(theta3) = 0, as discussed in the DeMers followup.
-
- However, this arm geometry (called the _articulated_arm_) also has internal
- workspace singularities. An easy way to find these singularities is to
- examine the plane formed by the axes of rotation of the first two joints.
- This (vertical) plane passes through the shoulder center, and rotates with
- theta1. Any time the controlled point on the forearm lies in this plane, the
- arm is also singular. Usually this "controlled point" is the center of the
- wrist, but it could be any point in space attached to this link. You cannot
- move the controlled point horizontally in this plane at these singularities.
-
- Steve
- --
-
- Steve Remis
- PhD Student
- University of Notre Dame
- sremis@tolstoy.helios.nd.edu
-