NetNews Usenet Archive 1992 #18/NN_1992_18.iso/spool/comp/lang/c/12228

Text File | 1992-08-12 | 1.8 KB | 50 lines

Newsgroups: comp.lang.c
Path: sparky!uunet!psinntp!commpost!opus!fia!camelot!jogulin
From: [e-mail] (Joseph Ogulin)
Subject: Re: Computer terms, etc
Message-ID: <[e-mail]>
Sender: jogulin@camelot (Joseph Ogulin)
Nntp-Posting-Host: camelot
Organization: The Rift from Here to There
References:  <[e-mail]>
Date: Tue, 11 Aug 1992 12:21:17 GMT
Lines: 37

In article <[e-mail]>, [e-mail] (Charles Evans) writes:
|> If anyone could help me, please define these for me:
|> and what is the diff. between  *foo[] and **foo?

I haven't experienced one, but *foo[] is an array of character pointers
and **foo is a pointer to a character pointer.

|> whats the diff in these?
|>
|> char *foo = "abc";
|> char *foo[] = "abc";

What you have as *foo[] = "abc"; is an illegal declaration.  You would have
to declare it as follows:

    char *foo[] = { "abc", 0 };

because you are declaring an array of pointers.  I can't recall if the 0 is
necessary in there (somebody help, I don't do those declarations normally).

|> char foo[] = "abc";
|> char foo[4] = "abc";  <--- is the '\0' autmatcially added?

Yes, the '\0' is automatically added, and there is nothing wrong with that
declaration, however, it is not good practice because what happens when you
want to change the string?  You have to be sure to change the size of the
character array too.

--
==> "You never f**king know the answer when it's important." --The Doctor <==
Joe Ogulin

[e-mail]        [e-mail]
[e-mail]        [e-mail]

Disclaimer:  The above article is solely my opinion and does not necessar-
ily reflect that of my employer.  The content is my responsibility alone.