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- Newsgroups: sci.physics.fusion
- Path: sparky!uunet!coplex!chuck
- From: chuck@coplex.com (Chuck Sites)
- Subject: Re: Implications of hypothesis of subground states
- Organization: Copper Electronics, Inc.
- Date: Tue, 26 Jan 1993 10:33:30 GMT
- Message-ID: <1993Jan26.103330.12036@coplex.com>
- References: <1993Jan21.192756.23373@ns.network.com> <1993Jan22.203403.1148@asl.dl.nec.com> <1993Jan24.085220.17739@coplex.com> <1993Jan25.011105.16977@ns.network.com>
- Lines: 55
-
- logajan@ns.network.com (John Logajan) writes:
-
- >chuck@coplex.com (Chuck Sites) writes:
- >>At what point does a hydrino become a neutron?
-
- >Never.
- >A neutron has a rest mass of 939.573 Mev/c^2
- >A proton has a rest mass of 938.280 Mev/c^2
- >An electron has a rest mass of 0.511003 Mev/c^2
-
- >If a MKF electron/proton pair didn't lose any energy/mass at all to radiation
- >then it would come out to be 939.573 - 938.28 - 0.511 = 0.782 Mev's too light
- >to be a neutron. But, of course, MKF claim each transistion does radiate,
- >thus in a fall from n=ground to n=1/210 (an orbit the size of the proton radius)
- >the MKF electron/proton pair lose an additional 0.6 Mev.
-
- And the winner is John! A neutron decays in 15.5 Hrs, by
- n -> p + e- + (anti)v_e
- because the neutron is 0.782ev too heavy and a half-spin in the wrong
- direction! I was half-heartedly kidding about neutron production from
- a hydrino collapse. Yet by electron capture,
- p + e- -> n + v_e
- I'm not going to suggest cold EC. MKF is basically the Borh model for one
- electron atoms taken to the extreem. It's the exact oposite of ionization,
- electron orbital collapse. The difference between an electron spiraling
- into the nucleus and MKF is that, MKF treats the photon as a wave and
- certain syncronous components of that wave are trapped by the electron
- charge density. If the phase of the trapped photon hits C, that
- component of the photon is emitted, and the shell collapses. It's
- pure and simple a 1/n Bohr model (a Bohr model all the way down to
- the nucleus).
-
- The implications are obvious, an absorbtion spectrum should be seen
- for 1/n and I understand Mill's claims that these lines have been
- seen in an UV sky survey. I'm skeptical that there is anything to
- this, but I'll see what I can find in the library.
-
- Have fun,
- Chuck Sites
- chuck@coplex.com
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