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- Date: Wednesday, 27 Jan 1993 15:58:27 EST
- From: <RVESTERM@vma.cc.nd.edu>
- Message-ID: <93027.155827RVESTERM@vma.cc.nd.edu>
- Newsgroups: rec.puzzles
- Subject: Re: Are you sure? NO - flame-resistant clothing ON <SPOILER>
- References: <1993Jan22.131719.36@janus.arc.ab.ca>
- <1993Jan25.145759.2592@cs.cornell.edu> <1993Jan26.115545.11556@eng.cam.ac.uk>
- <1993Jan26.121406.11680@eng.cam.ac.uk>
- Lines: 30
-
- the probability of A, given B, is the probability of A and B, divided
- by the probability of B. does anyone dare dispute me?
-
- no? good. to continue, let's dissect the question: "i have two children.
- at least one is a daughter. what's the chance that the other is a daughter?"
- is the same as "what is the chance that both of my children are female, given
- that at least one is female?" so we have that A is "both of my children are
- daughters", and B is "at least one of my two children is a daughter."
-
- so the chance that both are daughters given that one is a daughter is
- the chance that both are daughters AND at least one is a daughter, divided
- by the chance that at least one is a daughter.
-
- the chance that both are daughters and at least one is a daughter is
- the same as the chance that both are daughters (i.e., "at least one is
- a daughter" is a foregone conclusion, if both are daughters), which is
- one out of four.
-
- the chance that at least one is a daughter is one minus the chance that
- both are sons, which is one minus a quarter, which is three quarters.
-
- one quarter divided by three quarters is one third. last i checked,
- a third and a half were not the same.
-
- to all you proponents of the so-called "common sense" argument,
- remember the archaic definition of "common".
-
- bob vesterman.
-
-
-