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- Newsgroups: rec.puzzles
- Path: sparky!uunet!munnari.oz.au!cs.mu.OZ.AU!mundoe!adams
- From: adams@mundoe.maths.mu.OZ.AU (Tim Adam (c/o Jacinta))
- Subject: Re: Dividing apples (SPOILER)
- Message-ID: <9302623.14572@mulga.cs.mu.OZ.AU>
- Sender: adams@mundoe.maths.mu.oz.au (Tim Adam)
- Organization: Department of Mathematics, University of Melbourne
- References: <19706.2b62bd9d@ecs.umass.edu> <C1E5Du.D3B@news.rich.bnr.ca>
- Date: Tue, 26 Jan 1993 12:48:04 GMT
- Lines: 34
-
- >From: padmanab@ecs.umass.edu
- >Here is a SIMPLE problem I came across long ago.
- >I am posting it because I think it has a wonderful
- >solution.
- >
- >Suppose there are 25 identical apples. How many
- >ways can you divide them among three people? Also,
- >all the apples must be divided among them.
-
- In article <C1E5Du.D3B@news.rich.bnr.ca> bcash@crchh410.BNR.CA (Brian Cash) writes:
- >Is it 351? I figured it this way:
- > (etc...)
- >I'm rather math-impaired, so I would like to know 1) is this right? 2)
- >what is a more "scientific" way of finding the answer.
-
- The really nice way that I think the poser refers to is to think
- of picking two distinct numbers from 0 to 26 inclusive.
- Call the smaller x and the larger y.
- Then the first person gets x apples, the second y-x-1 apples,
- and the third 26-y. Note the most anyone can get is 25, the least 0,
- and the total is also 25.
- The number of ways of doing each of these things is the same.
- 27
- In this case, it is C or 27x26/2 or 351.
- 2
- This also generalizes easily, e.g. dividing 30 apples among 5 can be
- 34
- done C ways.
- 4
- Incidentally, I first came across this problem when studying quantum
- mechanics, which was the last place I expected to see combinatorics.
- ___________________________________________________________________
- Tim Adam, B.Sc./B.E.(Elec) student, Melbourne University, Australia
- Ph: (03) 807 3279 E-mail: tmadam@ee.mu.oz.au
-