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- Path: sparky!uunet!wupost!cs.utexas.edu!sun-barr!west.West.Sun.COM!smaug.West.Sun.COM!astro!richard
- From: Richard.Mathews@West.Sun.COM (Richard M. Mathews)
- Newsgroups: sci.physics
- Subject: Re: General Relativity Tests
- Date: 5 Jan 93 21:27:23 GMT
- Organization: Sunsoft Inc., Los Angeles, CA.
- Lines: 31
- Message-ID: <richard.726269243@astro>
- References: <rsf1.725654609@Ra.MsState.Edu>
- NNTP-Posting-Host: astro
- Keywords: Advancement in Perihelion, Einstein, Ritz, Tolman
- Originator: richard@astro
-
- rsf1@Ra.MsState.Edu (Robert S. Fritzius) writes:
- > m^2 c^2
- > 6 * pi * --- * ----- Tolman (8)
- > r^2 v^2
- >
- > 24 * pi v^2
- > ----------- * ----- Einstein (3)
- > (1 - e^2) c^2
- >
- >
- >Note that Tolman's (v^2/c^2) got inverted, as compared to that in the
- >simplified Einstein expression (3). Comments?
-
- First, you got the Einstein formula off by a factor of 4. You used
- <v> = pi * a / T when it should be <v> = 2 * pi * a / T. Thus the
- correct Einstein formula expressed as above should say "6 * pi".
-
- In the Tolman formula, note that for a circular Newtonian orbit,
- m / r = v^2 / G. Substituting this brings the v^2 back to the top.
- The differences in c's and G's are probably due to using c=G=1
- somewhere when deriving Eq 8 above (note that Eq 3 has the right
- units for an angle, but Eq 8 does not). The (1-e^2) is different
- because I used a circular orbit to get rid of Tolman's m.
-
- As for why retarded potentials added to Newtonian gravity is not the
- right answer: it may give the right periastron shift, but it does not
- conserve angular momentum.
-
- Richard M. Mathews D efend
- E stonian-Latvian-Lithuanian
- Richard.Mathews@West.Sun.COM I ndependence
-