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- Path: sparky!uunet!mcsun!fuug!kiae!demos!newsserv
- From: vignat@lnp01.jinr.dubna.su
- Newsgroups: sci.physics
- Subject: Re: QM question
- Date: Tue, 05 Jan 93 00:18:03 GMT
- Distribution: world
- Organization: unknown
- Message-ID: <3767.726182287@jinr.dubna.su>
- Sender: news-service@newcom.kiae.su
- Reply-To: vignat@lnp01.jinr.dubna.su
- Lines: 54
-
- > From: nariani@utdallas.edu (Sushil Nariani)
- > Message-ID: <BzuDo8.I9B@utdallas.edu>
- >
- > Scott Chase writes:
- > There is a difference between making a measurement of position and a
- > measurement of momentum for a free particle. Only the momentum is
- > a good quantum number, i.e., position does not commute with the Hamiltonian.
- > That is, position, in general, evolves in time, no matter what you do.
- > The rule you describe only applies when the operator *does* commute
- > with the Hamiltonian for the system.
- >
- > So what *does* happen when I make that sort of a measurement? In
- > general, what does measurement mean in QM and what is it's effect
- > on a system? [If this is in FAQ, please indicate without flames :-)
- >
- >
- > Since kinetic energy is p^2/2m, it will be very hard to construct a system
- > for which x is a good quantum number. I suppose you could imagine a
- > velocity-dependent potential which cancels the kinetic energy, though I
- > don't know what physical system this would describe. If position is a
- > good eigenvalue, then it will surely be very strange indeed.
- >
- > suppose you could devise such a system. It would still not leave
- > the particle in a delta function eigenstate, right?
- >
- > Sushil
- >
- Dear Sushil!
-
- Measurement in QM is capturing of some particle.
- Probability to capture a particle is proportional to energy of interaction
- with it, and the last is proportional to |\psi function|^2.
-
- You can easily construct a wave function with momentum and coordinate well
- defined simultaneously. Don't you believe? Look
-
- \psi = j_0(s|r-vt|)exp(ivr-i\omega t),
-
- where \omega = v^2/2+s^2/2 and j_0 is a spherical Bessel function, or
-
- j_0(x)=(sin x)/x.
-
- This wave function has a precise momentum (v, m=1, as you see) and a position,
- which is a point where it has the maximum. You can easily check, that it
- satisfies the Shroedinger equation.
-
- --
- ----------------------------------------------------------------------------
- Vladimir Ignatovich FLNP JINR, Tel. (09621)6-33-17 or (09621)4-70-65
- 141980 Dubna Moscow reg. Russia. Fax 7(095)-975-23-81 or 7(09621)-65-085
- TIME HAS INERTIA (Abian) so the PARTICLES to maintain their status quo must HAVE CONSCIOUSNESS (Nachmanson).
-
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