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- Path: sparky!uunet!lhdsy1!nntpserver.chevron.com!usno06.nor.chevron.com!hbtnn
- From: hbtnn@usno06.nor.chevron.com (Brian Tanner)
- Newsgroups: sci.math
- Subject: Re: Help me deal w/ infinity
- Message-ID: <1993Jan12.082517@usno06.nor.chevron.com>
- Date: 12 Jan 93 14:25:17 GMT
- References: <BzL73K.9xr@usenet.ucs.indiana.edu> <1992Dec23.030309.125@front.se> <11664@sun13.scri.fsu.edu> <1993Jan11.233051.26558@news.media.mit.edu>
- Sender: news@nntpserver.chevron.com (USENET News System)
- Organization: Chevron
- Lines: 25
-
- In article <1993Jan11.233051.26558@news.media.mit.edu>, minsky@media.mit.edu (Marvin Minsky) writes:
- |> In article <11664@sun13.scri.fsu.edu> jac@ds8.scri.fsu.edu (Jim Carr) writes:
- |> >In article <1992Dec23.030309.125@front.se> samuel@front.se writes:
- |> >>
- |> >>If this argument doesn't help, why don't ask your friends exactly how much
- |> >>they think that 0.999999... differs from 1.
- |> >
- |> >Good suggestion. I think this will help these poor souls examine the
- |> >unexamined assumption that are leading them to have trouble with the
- |> >proof, which is a very real difficulty with the fact that multiplying
- |> >.999.... by 10 does *not* change the number of 9s after the decimal
- |> >point! I would love to overhear their conversation:
- |> >
- |> >The difference is 1 times 10 to the something power, lets see... hmm,
- |> >it would seem that whatever power of 10 I choose, there is a larger
- |> >power I could use.... how many 9s are there again?
- |>
- |> Simpler answer: the difference is precisely 0.000000...
- |>
- |> Hmm. Or mabe it's 0.00000... or 0.0000000...
- |>
- |> Not so simple after all.
- |>
- "The square root of 3 is 2 for values of 3 which are very close to 4."
- (source forgotten)
-